The perimeters of two squares are 52 cm and 20 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of these two squares.

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  1. 36 cm
  2. 32 cm
  3. 44 cm
  4. 48 cm

Answer (Detailed Solution Below)

Option 4 : 48 cm
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UP Police Constable हिंदी (मॉक टेस्ट)
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Detailed Solution

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Given:

The perimeters of two squares are 52 cm and 20 cm.

Concept used:

Perimeter of square = 4 × side

Area = Side2

Calculation:

Side of first square =  = 13 cm

Side of second square =  = 5 cm

Area of first square = 13 × 13 = 169 cm2

Are of second square = 5 × 5 = 25 cm2

Difference in area = Area of third square = 169 - 25 = 144 cm2

Side of third square = √144 = 12 cm

Perimeter of third square = 4 × 12 = 48 cm.

∴ The perimeter of the third square is 48 cm.

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