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The points P(3, 2, 4), Q(4, 5, 2), R(5, 8, 0) and S(2 -1, 6) are

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  1. vertices of a rhombus which is not a square
  2. non-coplanar
  3. collinear
  4. coplanar but not collinear

Answer (Detailed Solution Below)

Option 3 : collinear
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Detailed Solution

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Concept:

Let A(x1, y1, z1) and B(x2, y2, z2)

Calculation:

Given points are P(3, 2, 4), Q(4, 5, 2), R(5, 8, 0) and S(2 -1, 6).

 

 

Here, We can write 3√14 = √14 + √14 + √14

⇒ RS = PQ + QR + PS

So, points are collinear.

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