The time period of a geostationary satellite is 24 h, at a height 6RE (RE is radius of earth) from surface of earth. The time period of another satellite whose height is 2.5 RE from surface will be,

Question

Question

Answer 1

CONCEPT:

According to Kepler's third law we have;

T² ∝ R³

Here we have T as the time period, and R is the radius.

CALCULATION:

The time period of the state is

T2 ∝ R3

For the first geostationary satellite we have, r₁ = R + 6R = 7R

The time period,T1 = 24 h

----(1)

For the second geostationary satellite we have, r2 = R + 2.5R = 3.5R

-----(2)

Now, on dividing the equation (1) by (2) we have;

Further solving we have;

h

Hence, option 3) is the correct answer.

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