The zeroes of the polynomial 4x2 - 3 will be:

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Bihar STET TGT (Maths) Official Paper-I (Held On: 04 Sept, 2023 Shift 1)
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  1. \(\frac{\sqrt3}{5}, -\frac{\sqrt3}{5}\)
  2. \(\frac{1}{2}, -\frac{1}{2}\)
  3. \(\frac{\sqrt3}{2}, -\frac{\sqrt3}{2}\)
  4. \(\frac{5}{3}, -\frac{5}{3}\)

Answer (Detailed Solution Below)

Option 3 : \(\frac{\sqrt3}{2}, -\frac{\sqrt3}{2}\)
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Detailed Solution

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Explanation -

The zeroes of a polynomial are the values of x that make the polynomial equal to zero. For the polynomial 4x2 - 3, we set the polynomial equal to zero and solve for x:

4x2 - 3 = 0

4x2 = 3

Dividing both sides by 4:

\(x^2 = \frac{3}{4}\)

Now, taking the square root of both sides:

\(x = \pm \sqrt{\frac{3}{4}}\)

Remember that the square root of a fraction breaks down into the square root of the numerator over the square root of the denominator:

\(x = \pm \frac{\sqrt{3}}{2}\)

Therefore, the zeroes of the polynomial 4x2 - 3 are \(x = \frac{\sqrt{3}}{2} \ \ and \ \ x = -\frac{\sqrt{3}}{2}.\)

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