Thermal decomposition of a Mn compound (X) at 513 K results in compound Y, MnO2 and gaseous product MnO2 reacts with NaCl and concentrated H2SO4 to give a pungent gas Z, X, Y and Z, respectively, are:

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JEE Mains Previous Paper 1 (Held On: 12 Apr 2019 Shift 2)
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  1. K3MnO4, K2MnO4 and Cl2
  2. K2MnO4, KMnO4 and SO2
  3. KMnO4, K2MnO4 and Cl2
  4. K2MnO4, KMnO4 and Cl2

Answer (Detailed Solution Below)

Option 3 : KMnO4, K2MnO4 and Cl2
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JEE Main 04 April 2024 Shift 1
90 Qs. 300 Marks 180 Mins

Detailed Solution

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Concept:

The thermal decomposition of potassium permanganate produces potassium manganate, manganese (IV) oxide, and oxygen. 

The thermal decomposition of an ‘Mn’ compound (X) is KMnO4 (potassium permanganate) at 513 K results in compound Y, K2MnO4 is (Potassium manganate) along with MnO2 (manganese (IV) oxide) and gaseous product. Here the MnO2 reacts with NaCl (sodium chloride) and concentrated H2 SO4 (sulfuric acid) to give a pungent gas Z is Cl2 (chlorine).

X = KMnO4

Y = K2MnO4

Z = Cl2

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