Question
Download Solution PDFWhat is the drop-in enthalpy (in kJ/kg) for a steam whistle which is perfectly insulated and does not work, has an exit velocity of steam at 40 m/sec?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
According to Steady Flow Energy Equation:
At 1 (steam enters the whistle) and 2 (steam leaves the whistle)
\({h_1} + \frac{{V_1^2}}{2} + g{z_1} + q = {h_2} + \frac{{V_2^2}}{2} + g{z_2} + w\)
Calculation:
As initial velocity is not given so V1 = 0 and No change in elevation (z1 = z2)
Q = 0 (perfectly insulated)
W = 0 (No work transfer)
\({h_1} = {h_2} + \frac{{V_2^2}}{2} ⇒ ({h_1} - {h_2})\times 10^3 = \frac{{V_2^2}}{2} = \frac{{{{40}^2}}}{2} = 0.8\;kJ/kg\)Last updated on Jul 1, 2025
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