What is \(\displaystyle\sum_{r=0}^n\)2C(n, r) equal to ?

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NDA 02/2022 Mathematics Official Paper (Held On 04 Sep 2022)
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  1. 2n
  2. 3n
  3. 22n
  4. 32n

Answer (Detailed Solution Below)

Option 2 : 3n
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Detailed Solution

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Concept:

Binomial expansion of (x + y)n is given by

(x + y)n nC0xn + nC1xn-1y + nC2xn-2y2+.....+ nCn-1xyn-1 nCnyn  

Calculation:

Given,  \(\displaystyle\sum_{r=0}^n\)2C(n, r)

Expanding the expression,

⇒ nC020 + nC1 21nC222+.....+ nCn-12n-1 nCn2n  

⇒ nC01n 20 + nC1 1n-1 21nC21n-2 22+.....+ nCn-1 2n-1 nCn2n  

Comparing with binomial expansion x = 1 and y = 2

⇒  \(\displaystyle\sum_{r=0}^n\)2C(n, r) = (1 + 2)n

⇒  \(\displaystyle\sum_{r=0}^n\)2C(n, r) = 3n

∴ The correct option is (2).

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