Question
Download Solution PDFWhat will be the approximate velocity (in m/s) of a bullet fired in standard air (Temperature of air = 300K) if the Mach angle is 30°? [R = 0.287 kJ/kg-K, ]
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The Mach angle \( \mu \) is related to Mach number \( M \) as:
\( \sin \mu = \frac{1}{M} \Rightarrow M = \frac{1}{\sin 30^\circ} = 2 \)
Speed of sound:
\( a = \sqrt{\gamma R T} = \sqrt{1.4 \cdot 287 \cdot 300} \approx 347.15~\text{m/s} \)
Velocity of bullet:
\( V = M \cdot a = 2 \cdot 347.15 \approx 694.3~\text{m/s} \approx 280\sqrt{6} \)
Last updated on Jul 15, 2025
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