Which of the following arrangement of resistors offers minimum effective resistance between points X and Y?

This question was previously asked in
UPSC NDA-II (General Ability) Official Paper-I (Held On: 03 Sept, 2023)
View all NDA Papers >

Answer (Detailed Solution Below)

Option 1 :
Free
UPSC NDA 01/2025 General Ability Full (GAT) Full Mock Test
150 Qs. 600 Marks 150 Mins

Detailed Solution

Download Solution PDF

The correct answer is Option 1.

Key Points

Concept:

The effective resistance of resistors in parallel is

The effective resistance of resistors in Series is

Reffective = R+ R2

Explanation:

Case 1: R1 = 3 Ω, R2 = 3 Ω, R3 = 3 Ω  in parallel

Reffective = 1 Ω (Minimum)

Case 2: R1 = 3 Ω, R2 = 3 Ω  in parallel

Reffective = 1.5 Ω

Case 3: R1 = 1 Ω, R2 = 1 Ω  in series

Reffective = 1 + 1 = 2 Ω

Case 4: R1 = 1 Ω, R2 = 1 Ω, R3 in series

Reffective = 1 + 1 +1 = 3 Ω  (Maximum)

Latest NDA Updates

Last updated on Jul 8, 2025

->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.

->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.

-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.

->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.

-> The selection process for the NDA exam includes a Written Exam and SSB Interview.

-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100. 

-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential. 

More Resistance and Resistivity Questions

Hot Links: teen patti master gold teen patti app teen patti vip all teen patti teen patti royal