Which of the following pair of equations represent the same conic-

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UP TGT Mathematics 2016 Official Paper
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  1. \(\frac{l}{r} = 1 + e\cos \theta \)\(\frac{l}{r} = 1 - e\cos \theta \)
  2. \(\frac{l}{r} = 1 + e\cos \theta \)\(\frac{l}{r} = - 1 + e\cos \theta \)
  3. \(\frac{l}{r} = 1 - e\cos \theta \)\(\frac{l}{r} = - 1 - e\cos \theta\)
  4. None of these

Answer (Detailed Solution Below)

Option 2 : \(\frac{l}{r} = 1 + e\cos \theta \)\(\frac{l}{r} = - 1 + e\cos \theta \)
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Detailed Solution

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Explanation -

The equation of the given curve \(\frac{l}{r} = 1 + e\cos θ \) .....(i)

Now (r, θ) and (-r, θ + π) represent the same point.

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So replace r  by -r and θ by θ + π  in the equation 1

We get -

⇒ \(\frac{l}{-r} = 1 + e\cos (θ+\pi) \)

We know that cos(θ + π) = - cosθ 

⇒ \(\frac{l}{-r} = 1 - e\cos (θ) \)

⇒ \(\frac{l}{r} = -1 + e\cos (θ) \) .....(2) 

Therefore equation (1) and (2) represents the same conic.

Hence \(\frac{l}{r} = 1 + e\cos θ \) &  \(\frac{l}{r} = -1 + e\cos (θ) \) represent the same conic.

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