Hooke’s law MCQ Quiz - Objective Question with Answer for Hooke’s law - Download Free PDF

Last updated on Jun 18, 2025

Latest Hooke’s law MCQ Objective Questions

Hooke’s law Question 1:

Hooke's law essentially defines _________

  1. Yield point 
  2. Strain 
  3. Stress
  4. Elastic  limit

Answer (Detailed Solution Below)

Option 4 : Elastic  limit

Hooke’s law Question 1 Detailed Solution

CONCEPT:

Hooke's law

  • Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.

⇒ Stress ∝ Strain

⇒  Stress = E × Strain

Where E = modulus of elasticity

F1 P.Y Madhu 08.04.20 D 2 

⇒  σ = Eϵ    

where σ = stress, ϵ = strain, and E = young's modulus of elasticity

EXPLANATION:

  • Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.
  • So the Hooke's law defines the elastic limit. Hence, option 3 is correct.

Hooke’s law Question 2:

A uniform cylinder of length \(L\) and mass \(M\) having cross-sectional area \(A\) is suspended, with its length vertical, from a fixed point by a massless spring, such that it is half submerged in a liquid of density \(\sigma\) at equilibrium position. The extension \(x_{0}\) of the spring when it is in equilibrium, is

  1. \(\dfrac{Mg}{k}(1-\dfrac{LA\sigma }{M})\)
  2. \(\dfrac{Mg}{k}(1-\dfrac{LA\sigma }{2M})\)
  3. \(\dfrac{Mg}{k}(1+\dfrac{LA\sigma }{M})\)
  4. \(\dfrac{Mg}{k}\)

Answer (Detailed Solution Below)

Option 2 : \(\dfrac{Mg}{k}(1-\dfrac{LA\sigma }{2M})\)

Hooke’s law Question 2 Detailed Solution

Let \(k\) be the spring constant of spring and it gets extended by length \(x_0\) in the equilibrium position. In equilibrium,

\(Kx_0 + F_B = Mg\)

\(\displaystyle kx_0 + \sigma \frac{L}{2} AG =Mg\)

\(\displaystyle x_0 =\frac {Mg - \dfrac{\sigma LAg}{2}}{k} =\frac {Mg}{k} \left ( 1 -\frac {\sigma LA}{2M} \right )\)


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Hooke’s law Question 3:

A uniform rod of mass m, length L, area of cross-section A and young’s modulus Y hangs from the ceiling. Its elongation under its own weight will be

  1. zero
  2. \(\frac{m g L}{2 A Y}\)
  3. \(\frac{m g L}{A Y}\)
  4. \(\frac{2 m g L}{A Y}\)

Answer (Detailed Solution Below)

Option 2 : \(\frac{m g L}{2 A Y}\)

Hooke’s law Question 3 Detailed Solution

Concept:

The young modulus is defined as the stress per unit strain i.e. \(Y=\frac{FL}{AΔ L}\) , where F is the force, L is the length , A is the cross sectional area Δ L is the change in length. It is the property of material. 

Explanation:

Let take the dx line element x distance from the origin. The young modulus will be

 \(Y=\frac{gxdm}{AΔ L} \\ Δ L= \frac{gxdm}{AY} \ \ \ \ \ \ \ \ \ \ (1)\)

And \(dm=\frac{mdx}{L}\)

Putting the dm in  (1).

\(Δ L= \frac{gm}{ALY}\int_0^Lxdx \\ Δ L= \frac{gmL}{2AY}\)

The correct option is (2).

 

Hooke’s law Question 4:

The length of a wire is 'L' and volume is V(fixed). If constant force F is applied on the wire, the extension produced in the wire will be proportional to _____

  1. L2
  2. 1/L
  3. 1/L2
  4. More than one of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : L2

Hooke’s law Question 4 Detailed Solution

CONCEPT:

  • Hooke's Law: For small deformations, the stress is proportional to the strain produced. 

Stress ∝ strain

stress = k × strain

where k is the proportionality constant.

  • Tensile stress:  The force applied along a rod divided by the cross-sectional area of the rod perpendicular to the applied force is called tensile stress.

\(\rm Tensile~stress = {Force \over Cross ~section ~area}\)

  • Longitudinal strain: When there is a change in length either due to tensile stress or due to compressive stress, the strain produced is longitudinal strain.

\(Longitudinal ~strain = {Change~in~length~or~extension \over original ~length}= {Δ L \over L}\)

EXPLANATION:

Given that length = L and volume = V and Force = F 

Since in the stress formula we have to use area A that is not given in the question, So

Volume V = Area A × length L

A = V / L

From Hooke's law

stress = k × strain

\( {F \over A}=k \times {Δ L \over L}\)

\( {F \over V/L}=k \times {Δ L \over L} \)

\( {F L \over V}=k \times {Δ L \over L} \)

\( {F L^2 \over k V}= {Δ L } \)

So extension ΔL ∝ L2

  • The extension produced in this wire by a constant force F is proportional to L2.
  • Hence the correct answer is option 4.

Hooke’s law Question 5:

Which of the following is the correct representation of Hooke's Law?

  1. stress ∝ strain
  2. stress ∝ 1/strain
  3. force ∝ 1/distance
  4. More than one of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : stress ∝ strain

Hooke’s law Question 5 Detailed Solution

CONCEPT:

  • Stress: Stress is the ratio of the load or force to the cross-sectional area of the material to which the load is applied.
    • The standard unit of stress is N/m2.
  • Strain: Strain is a measure of the deformation of the material as a result of the force applied.
    • The strain is a unitless quantity.
  • Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.

⇒ Strain ∝ Stress

⇒ Strain = E × Stress (Where E = modulus of elasticity)

F1 P.Y Madhu 08.04.20 D 2

  • Hooke's law is important because it helps us understand how a stretchy object will behave when it is stretched or compacted.
  • This law was named after Robert Hooke

EXPLANATION:

  • According to Hook's law, stress ∝ strain. So option 1 is correct.

Top Hooke’s law MCQ Objective Questions

According to Hooke’s law

  1. Stress \( \propto \frac{1}{{strain}}\)
  2. stress ∝ strain
  3. stress ∝ strain2
  4. stress \( \propto \frac{1}{{strai{n^2}}}\)

Answer (Detailed Solution Below)

Option 2 : stress ∝ strain

Hooke’s law Question 6 Detailed Solution

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CONCEPT:

  • Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.

⇒ Strain ∝ Stress

⇒ Strain = E × Stress (Where E = modulus of elasticity)

  • Hooke's law is important because it helps us understand how a stretchy object will behave when it is stretched or compacted.

EXPLANATION:

From the above explanation, we can see that according to Hooke’s law stress is directly proportional to strain:

i.e., \({\rm{Strain\;}} \propto {\rm{\;Stress}} \Rightarrow \frac{{stress}}{{strain}} = E\)

Hence option 2 is correct among all.

 Hooke's law states that with in the elastic limit ________ is porpotional to strain

  1. Stress
  2. Elastic moduli
  3. Force
  4. Weight

Answer (Detailed Solution Below)

Option 1 : Stress

Hooke’s law Question 7 Detailed Solution

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CONCEPT:

  • Hooke's law states that " Within the elastic limit stress is directly proportional to strain"
  • The stress of an elastic material is the restoring force acting per unit area of an object
  • The strain is the ratio of change in dimension to the original dimension 

EXPLANATION:

  • Hooke's law states that within the elastic limit stress is directly proportional to strainHence, option 1 is the answer
  • The ratio of stress to strain is known as an elastic modulus. 

Work done to increase a unit length of a wire is: (Y is the modulus of elasticity and S is strain).

  1. \(\dfrac{1}{2}Y^2S\)
  2. \(\dfrac{1}{3}YS^2\)
  3. \(\dfrac{1}{2}YS\)
  4. \( \dfrac{1}{2}YS^2\)

Answer (Detailed Solution Below)

Option 4 : \( \dfrac{1}{2}YS^2\)

Hooke’s law Question 8 Detailed Solution

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CONCEPT:

  • Stress (σ): Stress is the ratio of the load or force to the cross-sectional area of the material to which the load is applied.
  • The standard unit of stress is N/m2.
  • Stress (σ) = Force (F)/Area (A)
  • Strain (S): Strain is a measure of the deformation of the material as a result of the force applied.
  • The strain is a unitless quantity.

Work done in deforming a body is given by:

\(\begin{array}{l} W = \frac{1}{2}σ S \\ W = \frac{1}{2} × stress × strain \end{array}\)

  • Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.

⇒ Stress ∝ Strain

⇒  Stress (σ) = Y × Strain (S)  (Where Y = modulus of elasticity)

CALCULATION:

Work done (W) = (1/2) × stress × strain = (1/2) × Y × S × S = \( \dfrac{1}{2}YS^2\)

So option 4 is correct.

The substances that can be stretched to cause large strains are called ___________.

  1. plastic materials
  2. elastic materials
  3. elastomers
  4. None of the above

Answer (Detailed Solution Below)

Option 3 : elastomers

Hooke’s law Question 9 Detailed Solution

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CONCEPT:

  • Elastomers: The substances that can be stretched to cause large strains are called elastomers.
    • Examples are the tissue of the aorta, rubber, etc.
  • These materials do not obey Hooke’s law over most of the region.
  • A typical stress-strain graph of an elastomer is given below:

F1 Jitendra.K 27-04-21 Savita D1

Here we can clearly see that curve is not linear. To follow Hooke's law it is necessary that the curve should be in straight line.

EXPLANATION:

  • Option 1: Plastic materials are the materials which when deformed does not return to their original state or show permanent deformation.
  • Option 2: Elastic materials are the material which after deformation can regain their original shape and size.
  • Option 3: The materials that can be stretched to cause large strains are called elastomers.
  • So the correct answer is option 3.

Modulus of elasticity depends upon:

  1. Stress
  2. Strain
  3. Applied force
  4. None of these

Answer (Detailed Solution Below)

Option 4 : None of these

Hooke’s law Question 10 Detailed Solution

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CONCEPT:

  • Stress: Stress is the ratio of the load or force to the cross-sectional area of the material to which the load is applied.
    • The standard unit of stress is N/m2.
  • Strain: Strain is a measure of the deformation of the material as a result of the force applied.
    • The strain is a unitless quantity.
  • Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.

⇒ Strain ∝ Stress

⇒  Strain = E × Stress  (Where E = modulus of elasticity)

F1 P.Y Madhu 08.04.20 D 2

\( \Rightarrow σ=\frac{F(N)}{A(m^2)}\)    

\( \Rightarrow strain=\frac{dl}{l}\)    

\( \Rightarrow σ=strain\times E\)    

where σ = stress, F = applied force, A = cross-sectional area, dl = change in length, l = initial length and E = young's modulus of elasticity

EXPLANATION:

  • The young's modulus of elasticity is a proportionality constant and it depends on the material.
  • So modulus of elasticity does not depend on stress and strain.
  • Hence, option 4 is correct.

The work done in stretching a wire is_______.

  1. 1/2 (Force × Elongation)
  2. 2x (Stress × Strain)
  3. Stress × Strain
  4. Stress / Strain

Answer (Detailed Solution Below)

Option 1 : 1/2 (Force × Elongation)

Hooke’s law Question 11 Detailed Solution

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CONCEPT:

  • When we exert tensile stress on a wire, it will get stretched and work done in stretching the wire will be equal and opposite to the work done by inter-atomic restoring force. This work stored in the wire in the form of Elastic potential energy.
  • Whereas work done can be derived as

\(⇒ W\; = \smallint F.dl\)

Where F = force applied on wire and dl = change in length

EXPLANATION:

  • Now by using the relation of Young’s Modulus we can say that,

\(⇒ Y = \frac{F}{A} \times \frac{L}{{\rm{l}}} ⇒ F = \frac{{YAl}}{L}\)

Substituting the value of Y in the equation of work we get

\(⇒ W = \smallint \frac{{YAl}}{L}dl = \frac{{YA{l^2}}}{{2L}} = \frac{1}{2}\frac{YAl}{L}l\)

\(\Rightarrow W = \frac{1}{2}\times Force\times Elongation\)

Hooke's law essentially defines:

  1. Stress
  2. Strain
  3. Elastic limit
  4. None of these

Answer (Detailed Solution Below)

Option 3 : Elastic limit

Hooke’s law Question 12 Detailed Solution

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CONCEPT:

Hooke's law

  • Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.

⇒ Stress ∝ Strain

⇒  Stress = E × Strain

Where E = modulus of elasticity

F1 P.Y Madhu 08.04.20 D 2 

⇒  σ = Eϵ    

where σ = stress, ϵ = strain, and E = young's modulus of elasticity

EXPLANATION:

  • Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.
  • So the Hooke's law defines the elastic limit. Hence, option 3 is correct.

According to Hook's law, if stress is increased the ratio of stress to strain will _________

  1. increase
  2. decrease
  3. remain constant
  4. first increase then decrease

Answer (Detailed Solution Below)

Option 3 : remain constant

Hooke’s law Question 13 Detailed Solution

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CONCEPT:

  • Hooke's Law: For small deformations, the stress is proportional to the strain produced. 

Stress ∝ strain

stress = k × strain

where k is the proportionality constant. This constant is the property of the material and it is called Young's modulus of elasticity (γ).

EXPLANATION:

  • According to Hooke's law, we know that

stress = k × strain

\(k = {stress \over strain}\)

  • Here k is the ratio of stress and strain and this ratio is the property of the material and is constant.
  • So if we increase the stress value, the ratio of stress and strain (proportionality constant k) will not change because it remains constant.
  • Hence the correct answer is option 3.

Which of the following is the correct representation of Hooke's Law?

  1. stress ∝ strain
  2. stress ∝ 1/strain
  3. force ∝ 1/distance
  4. force ∝ velocity

Answer (Detailed Solution Below)

Option 1 : stress ∝ strain

Hooke’s law Question 14 Detailed Solution

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CONCEPT:

  • Stress: Stress is the ratio of the load or force to the cross-sectional area of the material to which the load is applied.
    • The standard unit of stress is N/m2.
  • Strain: Strain is a measure of the deformation of the material as a result of the force applied.
    • The strain is a unitless quantity.
  • Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.

⇒ Strain ∝ Stress

⇒ Strain = E × Stress (Where E = modulus of elasticity)

F1 P.Y Madhu 08.04.20 D 2

  • Hooke's law is important because it helps us understand how a stretchy object will behave when it is stretched or compacted.
  • This law was named after Robert Hooke

EXPLANATION:

  • According to Hook's law, stress ∝ strain. So option 1 is correct.

Robert Hooke is best known to physicists for his discovery of _____________.

  1. law of electricity
  2. law of elasticity
  3. law of flux
  4. law of gravity

Answer (Detailed Solution Below)

Option 2 : law of elasticity

Hooke’s law Question 15 Detailed Solution

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CONCEPT:

  • Robert Hooke is best known to physicists for his discovery of the law of elasticity. 
    • This Hookes' law laid the basis for stress and strain study and understanding how the elastic materials behave.
  • Ohm's law is known as the law of electricity. But there are also some other laws in the law of electricity.
  • Gauss founded the law of flux.
  • Newton founded the law of gravity.

EXPLANATION:

  • Robert Hooke is best known to physicists for his discovery of the law of elasticity.
  • So the correct answer is option 2.

Additional informaion

  • Some information about Robert Hooke:
    • He built a Gregorian reflecting telescope; discovered the fifth star in the trapezium and an asterism in the constellation Orion.
    • He suggested that Jupiter rotates on its axis; plotted detailed sketches of Mars which were later used in the 19th century to determine the planet’s rate of rotation
    • He stated the inverse square law to describe planetary motion, which Newton modified later etc. 
    • He built a Gregorian reflecting telescope.
    • He discovered the fifth star in the trapezium and an asterism in the constellation Orion.
    • He suggested that Jupiter rotates on its axis; plotted detailed sketches of Mars which were later used in the 19th century to determine the planet’s rate of rotation
    • He stated the inverse square law to describe planetary motion, which Newton modified later etc.
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