Hooke’s law MCQ Quiz - Objective Question with Answer for Hooke’s law - Download Free PDF
Last updated on Jun 18, 2025
Latest Hooke’s law MCQ Objective Questions
Hooke’s law Question 1:
Hooke's law essentially defines _________
Answer (Detailed Solution Below)
Hooke’s law Question 1 Detailed Solution
CONCEPT:
Hooke's law
- Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.
⇒ Stress ∝ Strain
⇒ Stress = E × Strain
Where E = modulus of elasticity
⇒ σ = Eϵ
where σ = stress, ϵ = strain, and E = young's modulus of elasticity
EXPLANATION:
- Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.
- So the Hooke's law defines the elastic limit. Hence, option 3 is correct.
Hooke’s law Question 2:
A uniform cylinder of length \(L\) and mass \(M\) having cross-sectional area \(A\) is suspended, with its length vertical, from a fixed point by a massless spring, such that it is half submerged in a liquid of density \(\sigma\) at equilibrium position. The extension \(x_{0}\) of the spring when it is in equilibrium, is
Answer (Detailed Solution Below)
Hooke’s law Question 2 Detailed Solution
\(Kx_0 + F_B = Mg\)
\(\displaystyle kx_0 + \sigma \frac{L}{2} AG =Mg\)
\(\displaystyle x_0 =\frac {Mg - \dfrac{\sigma LAg}{2}}{k} =\frac {Mg}{k} \left ( 1 -\frac {\sigma LA}{2M} \right )\)
Hooke’s law Question 3:
A uniform rod of mass m, length L, area of cross-section A and young’s modulus Y hangs from the ceiling. Its elongation under its own weight will be
Answer (Detailed Solution Below)
Hooke’s law Question 3 Detailed Solution
Concept:
The young modulus is defined as the stress per unit strain i.e. \(Y=\frac{FL}{AΔ L}\) , where F is the force, L is the length , A is the cross sectional area Δ L is the change in length. It is the property of material.
Explanation:
Let take the dx line element x distance from the origin. The young modulus will be
\(Y=\frac{gxdm}{AΔ L} \\ Δ L= \frac{gxdm}{AY} \ \ \ \ \ \ \ \ \ \ (1)\)
And \(dm=\frac{mdx}{L}\)
Putting the dm in (1).
\(Δ L= \frac{gm}{ALY}\int_0^Lxdx \\ Δ L= \frac{gmL}{2AY}\)
The correct option is (2).
Hooke’s law Question 4:
The length of a wire is 'L' and volume is V(fixed). If constant force F is applied on the wire, the extension produced in the wire will be proportional to _____
Answer (Detailed Solution Below)
Hooke’s law Question 4 Detailed Solution
CONCEPT:
- Hooke's Law: For small deformations, the stress is proportional to the strain produced.
Stress ∝ strain
stress = k × strain
where k is the proportionality constant.
- Tensile stress: The force applied along a rod divided by the cross-sectional area of the rod perpendicular to the applied force is called tensile stress.
\(\rm Tensile~stress = {Force \over Cross ~section ~area}\)
- Longitudinal strain: When there is a change in length either due to tensile stress or due to compressive stress, the strain produced is longitudinal strain.
\(Longitudinal ~strain = {Change~in~length~or~extension \over original ~length}= {Δ L \over L}\)
EXPLANATION:
Given that length = L and volume = V and Force = F
Since in the stress formula we have to use area A that is not given in the question, So
Volume V = Area A × length L
A = V / L
From Hooke's law
stress = k × strain
\( {F \over A}=k \times {Δ L \over L}\)
\( {F \over V/L}=k \times {Δ L \over L} \)
\( {F L \over V}=k \times {Δ L \over L} \)
\( {F L^2 \over k V}= {Δ L } \)
So extension ΔL ∝ L2
- The extension produced in this wire by a constant force F is proportional to L2.
- Hence the correct answer is option 4.
Hooke’s law Question 5:
Which of the following is the correct representation of Hooke's Law?
Answer (Detailed Solution Below)
Hooke’s law Question 5 Detailed Solution
CONCEPT:
- Stress: Stress is the ratio of the load or force to the cross-sectional area of the material to which the load is applied.
- The standard unit of stress is N/m2.
- Strain: Strain is a measure of the deformation of the material as a result of the force applied.
- The strain is a unitless quantity.
- Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.
⇒ Strain ∝ Stress
⇒ Strain = E × Stress (Where E = modulus of elasticity)
- Hooke's law is important because it helps us understand how a stretchy object will behave when it is stretched or compacted.
- This law was named after Robert Hooke.
EXPLANATION:
- According to Hook's law, stress ∝ strain. So option 1 is correct.
Top Hooke’s law MCQ Objective Questions
According to Hooke’s law
Answer (Detailed Solution Below)
Hooke’s law Question 6 Detailed Solution
Download Solution PDFCONCEPT:
- Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.
⇒ Strain ∝ Stress
⇒ Strain = E × Stress (Where E = modulus of elasticity)
- Hooke's law is important because it helps us understand how a stretchy object will behave when it is stretched or compacted.
EXPLANATION:
From the above explanation, we can see that according to Hooke’s law stress is directly proportional to strain:
i.e., \({\rm{Strain\;}} \propto {\rm{\;Stress}} \Rightarrow \frac{{stress}}{{strain}} = E\)
Hence option 2 is correct among all.Hooke's law states that with in the elastic limit ________ is porpotional to strain
Answer (Detailed Solution Below)
Hooke’s law Question 7 Detailed Solution
Download Solution PDFCONCEPT:
- Hooke's law states that " Within the elastic limit stress is directly proportional to strain"
- The stress of an elastic material is the restoring force acting per unit area of an object
- The strain is the ratio of change in dimension to the original dimension
EXPLANATION:
- Hooke's law states that within the elastic limit stress is directly proportional to strain. Hence, option 1 is the answer
- The ratio of stress to strain is known as an elastic modulus.
Work done to increase a unit length of a wire is: (Y is the modulus of elasticity and S is strain).
Answer (Detailed Solution Below)
Hooke’s law Question 8 Detailed Solution
Download Solution PDFCONCEPT:
- Stress (σ): Stress is the ratio of the load or force to the cross-sectional area of the material to which the load is applied.
- The standard unit of stress is N/m2.
- Stress (σ) = Force (F)/Area (A)
- Strain (S): Strain is a measure of the deformation of the material as a result of the force applied.
- The strain is a unitless quantity.
Work done in deforming a body is given by:
\(\begin{array}{l} W = \frac{1}{2}σ S \\ W = \frac{1}{2} × stress × strain \end{array}\)
- Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.
⇒ Stress ∝ Strain
⇒ Stress (σ) = Y × Strain (S) (Where Y = modulus of elasticity)
CALCULATION:
Work done (W) = (1/2) × stress × strain = (1/2) × Y × S × S = \( \dfrac{1}{2}YS^2\)
So option 4 is correct.
The substances that can be stretched to cause large strains are called ___________.
Answer (Detailed Solution Below)
Hooke’s law Question 9 Detailed Solution
Download Solution PDFCONCEPT:
- Elastomers: The substances that can be stretched to cause large strains are called elastomers.
- Examples are the tissue of the aorta, rubber, etc.
- These materials do not obey Hooke’s law over most of the region.
- A typical stress-strain graph of an elastomer is given below:
Here we can clearly see that curve is not linear. To follow Hooke's law it is necessary that the curve should be in straight line.
EXPLANATION:
- Option 1: Plastic materials are the materials which when deformed does not return to their original state or show permanent deformation.
- Option 2: Elastic materials are the material which after deformation can regain their original shape and size.
- Option 3: The materials that can be stretched to cause large strains are called elastomers.
- So the correct answer is option 3.
Modulus of elasticity depends upon:
Answer (Detailed Solution Below)
Hooke’s law Question 10 Detailed Solution
Download Solution PDFCONCEPT:
- Stress: Stress is the ratio of the load or force to the cross-sectional area of the material to which the load is applied.
- The standard unit of stress is N/m2.
- Strain: Strain is a measure of the deformation of the material as a result of the force applied.
- The strain is a unitless quantity.
- Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.
⇒ Strain ∝ Stress
⇒ Strain = E × Stress (Where E = modulus of elasticity)
\( \Rightarrow σ=\frac{F(N)}{A(m^2)}\)
\( \Rightarrow strain=\frac{dl}{l}\)
\( \Rightarrow σ=strain\times E\)
where σ = stress, F = applied force, A = cross-sectional area, dl = change in length, l = initial length and E = young's modulus of elasticity
EXPLANATION:
- The young's modulus of elasticity is a proportionality constant and it depends on the material.
- So modulus of elasticity does not depend on stress and strain.
- Hence, option 4 is correct.
The work done in stretching a wire is_______.
Answer (Detailed Solution Below)
Hooke’s law Question 11 Detailed Solution
Download Solution PDFCONCEPT:
- When we exert tensile stress on a wire, it will get stretched and work done in stretching the wire will be equal and opposite to the work done by inter-atomic restoring force. This work stored in the wire in the form of Elastic potential energy.
- Whereas work done can be derived as
\(⇒ W\; = \smallint F.dl\)
Where F = force applied on wire and dl = change in length
EXPLANATION:
- Now by using the relation of Young’s Modulus we can say that,
\(⇒ Y = \frac{F}{A} \times \frac{L}{{\rm{l}}} ⇒ F = \frac{{YAl}}{L}\)
Substituting the value of Y in the equation of work we get
\(⇒ W = \smallint \frac{{YAl}}{L}dl = \frac{{YA{l^2}}}{{2L}} = \frac{1}{2}\frac{YAl}{L}l\)
\(\Rightarrow W = \frac{1}{2}\times Force\times Elongation\)
Hooke's law essentially defines:
Answer (Detailed Solution Below)
Hooke’s law Question 12 Detailed Solution
Download Solution PDFCONCEPT:
Hooke's law
- Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.
⇒ Stress ∝ Strain
⇒ Stress = E × Strain
Where E = modulus of elasticity
⇒ σ = Eϵ
where σ = stress, ϵ = strain, and E = young's modulus of elasticity
EXPLANATION:
- Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.
- So the Hooke's law defines the elastic limit. Hence, option 3 is correct.
According to Hook's law, if stress is increased the ratio of stress to strain will _________
Answer (Detailed Solution Below)
Hooke’s law Question 13 Detailed Solution
Download Solution PDFCONCEPT:
- Hooke's Law: For small deformations, the stress is proportional to the strain produced.
Stress ∝ strain
stress = k × strain
where k is the proportionality constant. This constant is the property of the material and it is called Young's modulus of elasticity (γ).
EXPLANATION:
- According to Hooke's law, we know that
stress = k × strain
\(k = {stress \over strain}\)
- Here k is the ratio of stress and strain and this ratio is the property of the material and is constant.
- So if we increase the stress value, the ratio of stress and strain (proportionality constant k) will not change because it remains constant.
- Hence the correct answer is option 3.
Which of the following is the correct representation of Hooke's Law?
Answer (Detailed Solution Below)
Hooke’s law Question 14 Detailed Solution
Download Solution PDFCONCEPT:
- Stress: Stress is the ratio of the load or force to the cross-sectional area of the material to which the load is applied.
- The standard unit of stress is N/m2.
- Strain: Strain is a measure of the deformation of the material as a result of the force applied.
- The strain is a unitless quantity.
- Hooke's law states that within the elastic limit the stress applied on a body is directly proportional to strain produced.
⇒ Strain ∝ Stress
⇒ Strain = E × Stress (Where E = modulus of elasticity)
- Hooke's law is important because it helps us understand how a stretchy object will behave when it is stretched or compacted.
- This law was named after Robert Hooke.
EXPLANATION:
- According to Hook's law, stress ∝ strain. So option 1 is correct.
Robert Hooke is best known to physicists for his discovery of _____________.
Answer (Detailed Solution Below)
Hooke’s law Question 15 Detailed Solution
Download Solution PDFCONCEPT:
- Robert Hooke is best known to physicists for his discovery of the law of elasticity.
- This Hookes' law laid the basis for stress and strain study and understanding how the elastic materials behave.
- Ohm's law is known as the law of electricity. But there are also some other laws in the law of electricity.
- Gauss founded the law of flux.
- Newton founded the law of gravity.
EXPLANATION:
- Robert Hooke is best known to physicists for his discovery of the law of elasticity.
- So the correct answer is option 2.
- Some information about Robert Hooke:
- He built a Gregorian reflecting telescope; discovered the fifth star in the trapezium and an asterism in the constellation Orion.
- He suggested that Jupiter rotates on its axis; plotted detailed sketches of Mars which were later used in the 19th century to determine the planet’s rate of rotation
- He stated the inverse square law to describe planetary motion, which Newton modified later etc.
- He built a Gregorian reflecting telescope.
- He discovered the fifth star in the trapezium and an asterism in the constellation Orion.
- He suggested that Jupiter rotates on its axis; plotted detailed sketches of Mars which were later used in the 19th century to determine the planet’s rate of rotation
- He stated the inverse square law to describe planetary motion, which Newton modified later etc.