Problem on Age MCQ Quiz - Objective Question with Answer for Problem on Age - Download Free PDF

Given:

Present age of Karan = 25 years

In 5 years, the ratio of age of Karan to Sangeet = 6 : 7

Formula used:

Let the present age of Sangeet = x

After 5 years, age of Karan = 25 + 5 = 30 years

After 5 years, age of Sangeet = x + 5

Calculations:

The ratio of their ages after 5 years = 6 : 7

⇒ (30) / (x + 5) = 6 / 7

⇒ 7 × 30 = 6 × (x + 5)

⇒ 210 = 6x + 30

⇒ 6x = 210 - 30

⇒ 6x = 180

⇒ x = 180 / 6

⇒ x = 30

Present age of Sangeet = 30 years

Age of Sangeet four years ago = 30 - 4 = 26 years

∴ The age of Sangeet four years ago was 26 years.

Given:

A father's age is seven times that of his son's age.

Calculation:

Let the son's age be x years.

Father's age = 7x years

Father's age after 3 years: = 7x + 3

Son's age = x + 3

7x + 3 = 5(x + 3)

⇒ 7x + 3 = 5x + 15

⇒ 7x - 5x = 15 - 3

⇒ x = 6

Son's current age = 6 years

Father's current age = 7 × 6 = 42 years

Let y be the number of years after which their combined age will be 62.

(6 + y) + (42 + y) = 62

⇒ 6 + 42 + 2y = 62

⇒ 2y = 62 - 48

⇒ y = 7

∴ The correct answer is option (3).

Given:

The average age of A, B, and C is 45 years.

The average age of A, C, and D is 51 years.

The age of D is 56 years.

Formula Used:

Average = (Sum of quantities) / (Number of quantities)

Calculations:

According to the question:

Sum of ages of A, B, and C = 45 × 3 = 135 years

Sum of ages of A, C, and D = 51 × 3 = 153 years

Given that the age of D is 56 years, we can find the sum of ages of A and C:

Sum of ages of A and C = 153 - 56 = 97 years

Now, we know the sum of ages of A, B, and C is 135 years. Therefore, we can find the age of B:

Age of B = 135 - 97 = 38 years

∴ The age of B is 38 years.

Given:

Present age ratio of Manmohan and Manpreet = 7:6

After 6 years, their age ratio = 8:7

At the time of marriage, their age ratio = 4:3

Formula used:

Let the present ages of Manmohan and Manpreet be 7X and 6X, respectively.

After 6 years:

\( \frac{7X + 6}{6X + 6} = \frac{8}{7} \)

Calculation:

⇒ \( 7X + 6 = \frac{8}{7} × (6X + 6) \)

⇒ \( 7X + 6 = \frac{48X + 48}{7} \)

⇒  7(7X + 6) = 48X + 48   

⇒  49X + 42 = 48X + 48   

⇒  49X - 48X = 48 - 42    

⇒  X = 6   

Manmohan's present age =  7 × 6 = 42 

Manpreet's present age =  6 × 6 = 36 

Let their ages at the time of marriage be 4Y and 3Y.

So, \( \frac{42 - Y}{36 - Y} = \frac{4}{3} \)

⇒  3(42 - Y) = 4(36 - Y) 

⇒  126 - 3Y = 144 - 4Y 

⇒  126 - 144 = -4Y + 3Y 

⇒  -18 = -Y 

⇒  Y = 18 

∴ They got married 18 years ago.

Calculation

Let present age of P = x

So, present age of Q = 3x

Let present age of R = y

ATQ y – 1 = 2(x-1)

y=2x-1

And, 3x - 2x + 1 = 21

So, x= 20 [ Age of P]

So, 3x=60 [ Age pf Q]

So, y = 40 – 1 = 39 [ Age of R]

Required ratio = 60 : (39+3) = 10 : 7

Let the ages of the man and his wife be 5x and 8x respectively.

After ten years,

ratio of the man and his wife will be 2 : 3;

⇒ (5x + 10) / (8x + 10) = 2 : 3

Hence, x = 10

The ages of the man and his wife are 50 and 80 respectively.

Given:

Four years ago age ratio of Ram and Rahul = 3 : 4

Present age ratio of Ram and Rahul = 17 : 22

Calculation:

Four years ago age ratio of Ram and Rahul = 3x : 4x

According to the question

(3x + 4)/(4x + 4) = 17/22

⇒ 22 × (3x + 4) = 17 × (4x + 4)

⇒ 66x + 88 = 68x + 68

⇒ 68x – 66x = 88 – 68

⇒ 2x = 20

⇒ x = 10

Present age of Ram = 3 × 10 = 30 + 4 = 34

Present age of Sunil = 34 – 5 = 29 years 

∴ the correct answer is 29 years.

Shortcut Trick 

Many students ignore to read full question, So please read full question before solving it. 
In the last line of question there is mentioned that Ram is 5 years older than Sunil. 
So if you Calculate Ram's age than you also can calculate Sunil's age.

Given:

Karan was born 3 years after his parent's marriage.

His father is 6 years older than his mother but 26 years older than Karan.

Karan is 12 years of age as on today.

Calculation:

According to question,

⇒ F = 6 + M

⇒ F = 26 + K 

Since now karan is 12 years old so,

⇒ K = 12,

⇒ F = 38,

⇒ M = 32

Now at the time of birth age will be ,

⇒ F = 26

⇒ M = 20 

Since karan was born 3 years after his parents marriage so

Age of motrher = 20 - 3 = 17

∴ 'The correct answer is 17 years.

Given:

Manish age = 20 years

Greece age = 20/5 = 4 years

Let after x years Manish will become three times as old as Greece:

(20 + x) = 3 × (4 + x)

20 + x = 12 + 3x

2x = 8

x = 4

After 4 years Manish's age will be 24 years and Greece's age 8 years.

When Manish's age is 24 years old he became three times as old as Greece.

Hence, the correct answer is "24".

Given:

Amita's father was 38 years old when she was born.

Her mother was 36 years old when her brother was born.

Her brother was four years younger than her.

Calculation:

Let the present age of Amita be P years.

So,

The age of her father = (38 + P) years

The age of her brother = (P - 4) years

The age of her mother = 36 + (P - 4) = (32 + P) years

Now, the age difference between her parents = (38 + P) - (32 + P) = 6 years

∴ The difference between the ages of her parents is 6 years.

Given:

(Man's age + 15 years) = 4(Man's age - 15 years)

Calculation:

Let the present age of the man be x years

According to the question,

⇒ (x + 15) = 4(x - 15)

⇒ x + 15 = 4x - 60

⇒ 4x - x = 15 + 60

⇒ 3x = 75

⇒ x = 25

∴ The present age of man is 25 years.

Let the ages of Keshav and Danish after six years be 19x and 17x respectively

⇒ Present age of Keshav = (19x - 6) years

⇒ Present age of Danish = (17x - 6) years

According to question, age of Keshav 4 years ago is equal to present age of Danish

19x - 6 - 4 = 17x - 6

⇒ 2x = 4

⇒ x = 2

Present age of Keshav = (19 × 2) - 6 = 32 years

Present age of Danish = (17 × 2) - 6 = 28 years

Sum of their ages = 32 + 28 = 60

∴ The sum of their ages is 60.

Given:

Wife was born 23 years ago (which means her present age is 23 years

Ratio of ages of Rahul and his wife 7 years from now will be 7 : 6

Calculation:

Let the present age of husband be x years.

Age of husband 7 years hence = x + 7

Present age of wife = 23 years

Age of wife after 7 years = 30 years

According to the question,

Ratio of ages of husband and wife 7 years from now = 7 : 6

⇒ (x + 7)/30 = 7/6

⇒ x + 7 = 35

⇒ x = 28 years

Given:

5 years ago, ratio of ages of A, B and C = 4 : 5 : 7.

Sum of their present ages = 135 years.

Concept used:

Total = Average × Number of entities

Calculation:

Let the common ratio be Q.

So, 5 years ago, the ages of A, B, and C are 4Q, 5Q, and 7Q respectively.

Now, their present ages are (4Q + 5), (5Q + 5), and (7Q + 5) respectively.

According to the question,

(4Q + 5) + (5Q + 5) + (7Q + 5) = 135

⇒ 16Q + 15 = 135

⇒ 16Q = 135 - 15

⇒ 16Q = 120

⇒ Q = 7.5

The present age of B = (5 × 7.5 + 5) = 42.5 years

The present age of C = (7 × 7.5 + 5) = 57.5 years

Now, 3 years from now, the sum of the ages of B and C

⇒ (42.5 + 3) + (57.5 + 3)

⇒ 106 years

∴ After 3 years from now, the sum of the ages of B and C will be 106 years.

Given,

Let present age of Radha and Ram be a years and b years respectively.

⇒ (a - 6) : (b - 6) = 5 : 8

⇒ 8a - 48 = 5b - 30

⇒ 8a - 5b = 18

Then,

⇒ b - a = 6

Solving,

a = 16 years and b = 22 years

Then,

⇒ (16 + ?) : (22 + ?) = 13 : 16

⇒ 256 + 16? = 286 + 13?

⇒ ? = 10

∴ after 10 years ratio will become 13 :16.