Shallow Foundation MCQ Quiz - Objective Question with Answer for Shallow Foundation - Download Free PDF

Last updated on Jun 11, 2025

Latest Shallow Foundation MCQ Objective Questions

Shallow Foundation Question 1:

A fully compensated raft foundation for a building is

  1. Designed as a completely flexible raft
  2. Designed as a very rigid raft
  3. Such that the weight of the excavated soil is equal to the load due to the building
  4. Supported by piles of short length

Answer (Detailed Solution Below)

Option 3 : Such that the weight of the excavated soil is equal to the load due to the building

Shallow Foundation Question 1 Detailed Solution

Explanation:

A fully compensated raft foundation (also called buoyant raft) is designed so that the weight of the soil excavated for the foundation equals the weight of the building and the foundation combined.

  • This compensation reduces the net increase in stress on the soil, minimizing settlement.

  • It is especially useful in soft or compressible soils where minimizing settlement is critical.

  • The idea is that the removal of soil weight balances the load, so the foundation does not cause additional stress on the soil below.

Additional InformationRaft Foundation (or mat foundation) is a large, continuous slab supporting multiple columns and walls, spreading the load over a wide area. It is used when soil bearing capacity is low or loads are heavy.

Types of Raft Foundations

  • Rigid Raft: Assumes the raft acts as a stiff plate, distributing loads uniformly.

  • Flexible Raft: Assumes the raft bends and deflects under loads, distributing unevenly.

  • Fully Compensated Raft: Designed so that the weight of the soil excavated equals the weight of the building and foundation.

Fully Compensated Raft Foundation

  • Also known as buoyant foundation or compensated foundation.

  • The purpose is to neutralize the additional load on the soil by removing an equivalent weight of soil during excavation.

  • Reduces settlement by minimizing changes in stress on the underlying soil.

  • Commonly used in soft, compressible soils or areas with high water tables.

  • Helps prevent excessive consolidation and uneven settlement.

Shallow Foundation Question 2:

What is the main advantage of a raft foundation?

  1. Reduces column spacing
  2.  Settlement is uniform
  3. Easier to construct
  4. Cheaper than other foundations

Answer (Detailed Solution Below)

Option 2 :  Settlement is uniform

Shallow Foundation Question 2 Detailed Solution

Explanation:

  1. A raft foundation is a large slab that supports the building and spreads the load across the entire foundation area. This helps in evenly distributing the weight across the soil.

  2. It is particularly useful when the soil is weak or highly variable in terms of load-bearing capacity, as it minimizes differential settlement.

  3. By spreading the load, it ensures uniform settlement, reducing the risk of cracks or structural issues in the building.

Additional InformationPile Foundations:

  1. Deep Foundation
    A pile foundation is a type of deep foundation that transfers the load of a structure to deeper, more stable soil or bedrock, often used when the surface soil is not strong enough to support the load.

  2. Types of Piles
    Piles can be pre-cast concrete, steel, or timber and can either be driven (hammered into the ground) or bored (drilled and filled with concrete).

  3. Used in Weak Soils
    Pile foundations are commonly used in areas with weak or compressible surface soils, such as swamps, soft clay, or loose sands, to provide stability to buildings and structures.

  4. Load Distribution
    Piles transmit the load of the structure through weak soil layers and into stronger soil or rock beneath. This helps in resisting both vertical loads and lateral forces such as wind or seismic activity.

  5. Types of Pile Foundations
    There are different types of pile foundations based on the method of installation: friction piles (rely on friction between the pile surface and surrounding soil) and end-bearing piles (transfer load to a firm rock or soil layer at the pile tip).

Shallow Foundation Question 3:

Consider the following statements

1. Terzaghi’s theory is applicable for shallow foundation only.

2. Meyerhoff theory is applicable for shallow and deep foundation both.

The correct statement are.

  1. 1 only
  2. 2 only
  3. Both 1 and 2
  4. None of the above
  5. Information Insufficient

Answer (Detailed Solution Below)

Option 3 : Both 1 and 2

Shallow Foundation Question 3 Detailed Solution

Explanation:

Based on the Assumptions, Terzaghi’s Theory is applicable for shallow foundation because side shear resistance and stressing of soil above the foundation is ignored whereas,

Meyerhoff considered stress zone extended up to G.L. Hence Meyershoff's theory is applicable for deep footing also.

Hence, both statements are correct.

Shallow Foundation Question 4:

A rigid isolated footing is resting on Clay. The contact pressure at the edges and centre of the footing are respectively:

  1. Maximum and minimum
  2. Minimum and maximum
  3. Zero and maximum
  4. Maximum and zero
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : Maximum and minimum

Shallow Foundation Question 4 Detailed Solution

Concept:

Variation of contact pressure and settlement of footing on different types of soil is as follows:

1. Flexible footing:

Case-I: Resting on Sand

  • Settlement: Maximum at edges and minimum at the center
  • Contact Pressure: Uniform

Case-II: Resting on Clay

  • Settlement: Minimum at edges and maximum at the center
  • Contact Pressure: Uniform

F1 N.M Madhu 21.03.20 D1

2. Rigid footing:

Case-I: Resting on Sand

  • Settlement: Uniform
  • Contact Pressure: Zero at edges and maximum at the center

Case-II: Resting on Clay

  • Settlement: Uniform
  • Contact Pressure: maximum at edges and minimum at the center
F1 N.M Madhu  21.03.20 D2

Shallow Foundation Question 5:

Observed N-value of an SPT test is 21. The N-value after correcting for dilatancy is

  1. 18
  2. 21
  3. 19
  4. 15
  5. 36

Answer (Detailed Solution Below)

Option 1 : 18

Shallow Foundation Question 5 Detailed Solution

Concept;

Dilatancy correction:

It is to be applied when No obtained after overburden correction, exceeds 15 in saturated fine sands and silts. IS: 2131-1981 incorporates the Terzaghi and Peck recommended dilatancy correction (when No > 15) using the equation

\(\rm N= 15 + \frac{1}{2}\left( {N_0-\;15} \right)\)

N0 - SPT value after overburden correction

Calculation:

Given: N0 = 21

\(\rm N= 15 + \frac{1}{2}\left( {21-\;15} \right)\)

⇒ N = 18

Top Shallow Foundation MCQ Objective Questions

A strip footing is resting on the ground surface of a pure clay bed having an undrained cohesion cu. The ultimate bearing capacity of the footing is equal to

  1. 2πcu
  2. πcu
  3. (π + 1)cu
  4. (π + 2)cu

Answer (Detailed Solution Below)

Option 4 : (π + 2)cu

Shallow Foundation Question 6 Detailed Solution

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Ultimate bearing capacity for a strip footing is

\({q_u} = C{N_c} + \gamma {D_f}{N_q} + 0.5\gamma B{N_\gamma }\)

For pure clay, Nc = 5.14, N= 1 and Nγ = 0 (∵ assuming smooth footing)

Footing is on the ground surface i.e. D = 0

qu = cuNc

q= 5.14 cu

q= (π + 2)cu

Two footings, one circular and the other strip, are founded on the surface of a purely Cohesionless soil. Diameter of the circular footing and width of strip footing is same. Then, the ratio of ultimate bearing capacity of circular to strip footing is:

  1. 0.75
  2. 0.60
  3. 1.20
  4. 1.33

Answer (Detailed Solution Below)

Option 2 : 0.60

Shallow Foundation Question 7 Detailed Solution

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Concept:

According to Tarzaghi,

Ultimate bearing capacity of circular footing

\({q_u} = 1.3C{N_c} + q{N_q} + 0.3Dγ {N_γ }\)

Ultimate bearing capacity of strip footing

\({q_u} = C{N_c} + q{N_q} + 0.5Bγ {N_γ }\)

For square footing, ultimate bearing capacity,

qu = 1.3 CNc + γDfNq + 0.4 γBNγ

Where,

C = cohesion 

Nc, Nq, Nγ = Bearing capacity factors

q = overburden pressure = γDf

Df = depth of the footing, B = width of footing, D = diameter of circular footing

γ = unit weight of soil

Calculation:

Given,

D = B

Surface footing ⇒ Df = 0 ⇒ q = 0

Purely cohesionless ⇒ C = 0

\(Ratio = \frac{{{q_{u,circular}}}}{{{q_{u,strip}}}} = \frac{{0.3D\gamma {N_\gamma }}}{{0.5B\gamma {N_\gamma }}} = 0.60\)

During plate load test, the settlement of a 35 cm plate is found to be 2 cm in a cohesive soil, then the settlement of square footing of 85 cm side under same loading conditions is ________.

  1. 3.75 cm
  2. 3.89 cm
  3. 4.85 cm
  4. 2.00 cm

Answer (Detailed Solution Below)

Option 3 : 4.85 cm

Shallow Foundation Question 8 Detailed Solution

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Concept:

Plate Load Test:

It is a field test to determine the ultimate bearing capacity of soil and the portable settlement under a given loading.

Bearing Capacity Calculation for Clayey Soils

\(Ultimate\: bearing\: capacity\:[q_u(f)] = Ultimate\: load\: for\: plate\:[q_u(p)]\)

Bearing Capacity Calculation for Sandy Soils

\(Ultimate\: bearing\: capacity\:[q_u(f)] = {Width\: of\: pit (Bf) \over Size\: of\: Plate (Bp)}\times q_u(p)\)

Settlement of plate in clayey soil:

\(​\dfrac{S_P}{S_F} = \dfrac{B_P}{B_F}\)

Settlement of plate in sandy soil:

\(\dfrac{S_P}{S_F} = \left(\dfrac{B_P(B_F + 0.3)}{B_F(B_P + 0.3)}\right)^2\)

Where

Sf = settlement of foundation

Sp = settlement of plate

Bf = width of footing/foundation

Bp = width of plate

Calculation:

Given data,

Width of plate(Bp) = 35 cm, SP = 2 cm

Width of footing(Bf) = 85 cm

Settlement of footing(SF) in clayey soil:

\(​\dfrac{S_P}{S_F} = \dfrac{B_P}{B_F}\)

\(​\dfrac{2}{S_F} = \dfrac{35}{85}\)

SF = 4.85 cm

Observed N-value of an SPT test is 21. The N-value after correcting for dilatancy is

  1. 18
  2. 21
  3. 19
  4. 15

Answer (Detailed Solution Below)

Option 1 : 18

Shallow Foundation Question 9 Detailed Solution

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Concept;

Dilatancy correction:

It is to be applied when No obtained after overburden correction, exceeds 15 in saturated fine sands and silts. IS: 2131-1981 incorporates the Terzaghi and Peck recommended dilatancy correction (when No > 15) using the equation

\(\rm N= 15 + \frac{1}{2}\left( {N_0-\;15} \right)\)

N0 - SPT value after overburden correction

Calculation:

Given: N0 = 21

\(\rm N= 15 + \frac{1}{2}\left( {21-\;15} \right)\)

⇒ N = 18

As per IS 2131 - 1981, the drive weight used in standard penetration test (SPT) is ______ KG

  1. 50
  2. 63.5
  3. 42.5
  4. 75

Answer (Detailed Solution Below)

Option 2 : 63.5

Shallow Foundation Question 10 Detailed Solution

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Explanation:

SPT test can be conducted to determine:

a) Relative Density of sands

b) Angle of internal friction

c) Unconfined compressive strength of clays

d) Ultimate bearing capacity on the basis of shear criteria

e) Allowable bearing pressure on the basis of settlement criteria

In this test, the split spoon sampler is driven by dynamic mechanism of hammer. This test is conducted either at every 2 to 5 meter interval or at the change of stratum.

Note:

The weight of the hammer is 63.5 kg.

The height of free fall is 750 mm or 75 cm.

The inner and outer diameter of the sampler is 35 mm and 50.5 mm respectively.

A square footing for a column carries a total Load (including the self-weight of footing) of 1760 KN. The safe bearing capacity of soil is 200 kN/m2. Using M 20 grade concrete and Fe415 steel, the area of footing (rounded to the nearest integer) will be

  1. 9 m2
  2. 2 m2
  3. 25 m2
  4. 16 m2

Answer (Detailed Solution Below)

Option 1 : 9 m2

Shallow Foundation Question 11 Detailed Solution

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Concept:

The area of footing (Af) is given by

\(\rm A_f = \rm\frac{{Total~ load}}{{{Safe ~bearing ~capacity}}}\)

Calculation:

Given:

Total load = 1750 kN, Safe bearing capacity = 200 kN/m2

\(\rm A_f = \rm\frac{{Total~ load}}{{{Safe ~bearing ~capacity}}}\)

\(A_f = \frac{{1760}}{{200}} = 8.8\;{m^2} \approx9 m^2\)

What is the maximum permissible differential settlement for isolated foundation on clay as per I.S. code?

  1. 25 mm
  2. 40 mm
  3. 25 mm to 40 mm
  4. 65 mm

Answer (Detailed Solution Below)

Option 2 : 40 mm

Shallow Foundation Question 12 Detailed Solution

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Explanation:

IS code specification for permissible settlement:

(i) Total Permissible settlement:

  • For isolated footing on clay = 65 mm
  • For isolated footing on sand = 40 mm
  • For raft footing on clay = 65-100 mm
  • For raft footing on sand = 40-65 mm


(ii) Permissible Differential settlement:

  • For isolated footing on clay = 40 mm
  • For isolated footing on sand = 25 mm


(iii) Permissible angular settlement:

  • For high framed structure < 1/500
  • To prevent all type of minor damage < 1/1000


Note: For multi-storeyed buildings having isolated foundations on sand, the maximum permissible settlement is 60 mm [ For multistorey buildings having isolated foundations take the higher load as compare to single storey buildings having isolated foundations. So that deflection caused by multistorey building having isolated foundation higher than 40 mm (from the safer side)]

The type of footing in which the load bearing structures share the common rectangular or trapezoidal footing is called:

  1. eccentric footing
  2. stepped footing
  3. combined footing
  4. isolated footing

Answer (Detailed Solution Below)

Option 3 : combined footing

Shallow Foundation Question 13 Detailed Solution

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Explanation:
Types of footings and their characteristics:

Types of footings Characteristics

 a. Combined footing

 I. For two or more columns

  • If the loads are equal then it is constructed in a rectangular shape.
  • For unequal loading its constructed in a trapezoidal shape.

 b. Mat foundation

 II. For supporting all
 columns of the structure.

  • When the allowable bearing pressure is very low, then this is adopted.
  • Raft is also used to reduce settlement is highly compressible soil by making the wt. of the structure and raft approximately equal to the soil excavated.

 c. Pile foundation

 III. For isolated or group of
 columns.

  • When the strength of the soil layer is very low or less and the incoming load is very high then pile foundation is adopted.
  • It goes deep into the ground and transfers the load to strong solid strata.
  • It is also used to increase the load-bearing capacity of soil by installing a group of piles.

 d. Isolated footing

 IV. For individual column.

  • It is constructed right below a column and above a strong soil layer and dissipates the load to the much larger area beneath it.

F5 Savita Engineering 29-7-22 D7

According to Rankine's formula minimum depth of foundation when q = 180 kN/m2, γ = 20 kN/m3 and ϕ = 30° is -

  1. 1.0 m
  2. 0.75 m
  3. 0.50 m
  4. 2.0 m

Answer (Detailed Solution Below)

Option 1 : 1.0 m

Shallow Foundation Question 14 Detailed Solution

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Concept:

Rankine's formula provides guidance on the minimum depth of foundation based on the bearing capacity of the soil.

\(q_u={\gamma } {D_f}\left( {\frac{{1 +\sin \varphi }}{{1 - \sin \varphi }}} \right)^2\)

Therefore the depth of the foundation can be expressed as,

\(D_f = \frac{q_u}{\gamma }\left( {\frac{{1 - \sin ϕ }}{{1 + \sin ϕ }}} \right)^2\)

Where D= Minimum depth of foundation, qu = Ultimate bearing capacity of the soil

Calculation:

Intensity of loading (qu) =180 kN/m2,

Unit weight = 20 kN/m3 and angle of internal friction (ϕ) = 30°

Depth of foundation = \(D_f = \frac{180}{20 }\left( {\frac{{1 - \sin 30° }}{{1 + \sin 30° }}} \right)^2\)

Depth of foundation (Df) = 1.0 m

Hence, According to Rankine's formula, the minimum depth of foundation is 1.0 m.

Identify the INCORRECT option.

SPT-N-values are correlated with:

  1. sensitivity
  2. unit weight
  3. angle of internal friction
  4. relative density

Answer (Detailed Solution Below)

Option 1 : sensitivity

Shallow Foundation Question 15 Detailed Solution

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Explanation:

NOTE: We have to find the incorrect statement from the given statements.

Standard Penetration Test: Standard penetration test can be used to determine:

  • Relative density of sand
  • Angle of internal friction (ϕ)
  • Unconfined compressive strength of clay
  • Ultimate bearing capacity on the basis of shear criteria
  • Allowable bearing pressure on the basis of settlement criteria
  • Load carrying capacity of pile
     

For standard penetration test:

(i) It is performed as a guideline in IS: 2131-1981 in the clean hole of 55 to 150 mm in diameter.

(ii) A thick wall split-tube sampler, 50.8 mm outer diameter and 35 mm inner diameter, is driven into the undisturbed soil at the bottom of the hole under the blows of a 65 kg drive weight with 75 cm free fall.

(iii) The minimum open length of the sampler should be 60 cm. It is first driven through 15 cm as a seating drive and is further driven through 30 cm or until 100 blows have been applied.

(iv) The number of blows required to drive the sampler 30 cm beyond the seating drive, is termed the penetration resistance N or SPT number.

The final SPT number is related to friction angle and relative density. which is given in the table

 Penetration  Resistance  (N) Relative Density or consistency  %age   relative  density  Approximate moist density in kN/m3  Approximate ϕ  in degrees
- - 0 - -
4 Very loose 15% 11.2-11.6 20° 
10 Loose 35% 14.4-18.4 30°
20 Moderately dense 50% 16-19.8 32° 
30 Medium dense 65% 17.6-20.8 36° 
50 Dense 85% 17.6-22.4 42° 
>50 Very dense 100% 20.8-24.0 45° 
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