Thief MCQ Quiz - Objective Question with Answer for Thief - Download Free PDF
Last updated on Jun 17, 2025
Latest Thief MCQ Objective Questions
Thief Question 1:
A thief running at 8 kms /hour is chased by a policeman whose speed is 10 km/hour. If the thief is 100 meters ahead of the policeman at the commencement of the chase then the time required for the policeman to catch the thief will be
Answer (Detailed Solution Below)
Thief Question 1 Detailed Solution
Given:
Speed of the thief = 8 km/hour.
Speed of the policeman = 10 km/hour.
Distance between thief and policeman = 100 meters = 0.1 km.
Formula Used:
Time = Distance / Relative Speed
Calculation:
Relative Speed = Speed of policeman - Speed of thief
Relative Speed = 10 km/hour - 8 km/hour
Relative Speed = 2 km/hour
Time = Distance / Relative Speed
Time = 0.1 km / 2 km/hour
Time = 0.05 hours
Time = 0.05 hours × 60 minutes/hour
Time = 3 minutes
The time required for the policeman to catch the thief is 3 minutes.
Thief Question 2:
A gunman is chasing a thief. He fires a shot to warn the thief. The thief heard the sound of gunshot after 7.5s. Find how far the thief is from the gunman (use the fact that sound travels at a speed of 340 m/s).
Answer (Detailed Solution Below)
Thief Question 2 Detailed Solution
Given:
The time taken for the sound to reach the thief = 7.5 seconds
Speed of sound = 340 m/s
Formula Used:
Distance = Speed × Time
Calculations:
Distance = 340 m/s × 7.5 s
Distance = 2550 meters
∴ The thief is 2550 meters away from the gunman.
Thief Question 3:
A thief seeing a policeman from a distance of 525 metres started running at a speed of 18 km/h. The policeman chased him immediately with a speed of 27 km/h. What is twice the distance covered by the policeman to catch the thief?
Answer (Detailed Solution Below)
Thief Question 3 Detailed Solution
Given:
Initial distance between thief and policeman = 525 m
Speed of thief = 18 km/h = 18 x 1000 ÷ 3600 = 5 m/s
Speed of policeman = 27 km/h = 27 x 1000 ÷ 3600 = 7.5 m/s
Formula used:
Relative Speed = Policeman speed − Thief speed
Time = Distance ÷ Relative Speed
Distance covered = Policeman speed x Time
Twice the distance = 2 x (Distance covered by policeman)
Calculations:
Relative Speed = 7.5 − 5 = 2.5 m/s
Time = 525 ÷ 2.5 = 210 sec
Distance covered = 7.5 x 210 = 1575 m
Twice the distance = 2 x 1575 = 3150 m
∴ Twice the distance covered by the policeman to catch the thief is 3150 metres.
Thief Question 4:
A policeman and a thief start from the same place and walk at the rate of 5 km/h and 5.5 km/h, respectively. How much time will they take to be 9.5 km apart, if they walk in the same direction?
Answer (Detailed Solution Below)
Thief Question 4 Detailed Solution
Given:
Speed of the policeman = 5 km/h
Speed of the thief = 5.5 km/h
They need to be 9.5 km apart
Formula used:
Relative speed = Speed of the thief - Speed of the policeman
Time = Distance / Relative speed
Calculation:
Relative speed = 5.5 - 5 = 0.5 km/h
⇒ Time = 9.5 / 0.5
⇒ Time = 19 hours
∴ The correct answer is option (4).
Thief Question 5:
A thief is spotted by a policeman from a distance of 400 metres. When the policeman starts to chase the thief also starts running. If the speed of the thief is18 km/h and that of the policeman 20 km/h, then how far would the thief have run before he is overtaken?
Answer (Detailed Solution Below)
Thief Question 5 Detailed Solution
Given:
Distance between policeman and thief = 400 metres
Speed of the thief = 18 km/h
Speed of the policeman = 20 km/h
Formula used:
Relative speed = Speed of the policeman - Speed of the thief
Distance = Relative speed × Time
Calculation:
Relative speed = 20 km/h - 18 km/h = 2 km/h
Distance to be covered by the policeman to catch the thief = 400 metres = 0.4 km
⇒ Time taken to catch the thief = Distance / Relative speed
⇒ 0.4 km / 2 km/h = 0.2 hours
⇒ Distance covered by the thief = Speed of the thief × Time
⇒ 18 km/h × 0.2 hours = 3.6 km
∴ The correct answer is option 2.
Top Thief MCQ Objective Questions
A thief committed a crime and escaped from the spot at a speed of 12 m/h. A Security guard started chasing him 20 minutes after the thief started running and caught him in the next 20 minutes. What is the speed (in m/h) of the Security guard?
Answer (Detailed Solution Below)
Thief Question 6 Detailed Solution
Download Solution PDFConcept used:
Speed × time = distance
Calculation:
In the 1st 20 min the thief cover distance = 4 m,
20 min in hour = 20/60 hour
Let's assume that the speed of security guard = x m/hr, where x > 12
According to the question,
⇒ (x - 12) × 20/60 = 4
⇒ x - 12 = 12
⇒ x = 24
∴ The correct answer is 24 m/h
A thief is spotted by a constable from 200 m. When the constable starts the chase, the thief also starts running. If the speed of the constable is 8 km/h and thief runs at the speed of 6 km/h, then how far (in m) will the thief be able to run before he is overtaken?
Answer (Detailed Solution Below)
Thief Question 7 Detailed Solution
Download Solution PDFGiven:
Distance between constable and thief = 200 m
Speed of constable = 8 km/h
Speed of thief = 6 km/h
Formula used:
Distance = relative speed × time
Calculation:
Distance = relative speed × time
⇒ 200 = (8 - 6) × (5/18) × time
⇒ 200 = 2 × (5/18) × time
⇒ Time = (200 × 18)/10
⇒ Time = 360 sec
Distance covered by thief = 6 × (5/18) × 360
⇒ 6 × 100 = 600 m
∴ The correct answer is 600 m.
A policeman noticed a thief from 300 m. The thief started running and the policeman was chasing him. The thief and the policeman ran at the speeds of 8 km/h and 9 km/h, respectively. What was the distance between them after 3 minutes?
Answer (Detailed Solution Below)
Thief Question 8 Detailed Solution
Download Solution PDFGiven:
Distance between policeman and thief in the starting = 300 m
Speed of policeman = 9 km/hr
Speed of thief = 8 km/hr
Concept: /Formula:
If the speed of a policeman and thief is x km/hr and y km/hr, then
Relative speed, if same directions = (x – y) km/hr
Distance between them after n hrs = (x – y) × n
1 km/hr = 5/18 m/sec
1 min = 60 sec
Calculation:
3 min = 3 × 60 = 180 seconds
Distance between policeman and thief in starting = 300 m
Relative speed of policeman and thief, if same directions = (9 – 8) = 1 × (5/18) = (5/18) m/sec
Distance covered in 180 seconds = (5/18) × 180 = 50 m
Distance between them after 180 seconds= 300 – 50 = 250 m
∴ Distance between them after 3 min is 250 m.
A policeman follows a thief who is 600 m ahead of the policeman. If the policeman and the thief run at speeds of 10 km/h and 8 km/h, respectively, in how much time (in minutes), will the policeman catch the thief?
Answer (Detailed Solution Below)
Thief Question 9 Detailed Solution
Download Solution PDFGiven:
Distance between policeman and thief = 600 m
Speed of policeman = 10 km/h
Speed of thief = 8 km/h
Formula used:
Distance = relative speed × time
Calculation:
Distance = relative speed × time
⇒ 600 = (10 - 8) × (5/18) × time
⇒ Time = (600 × 18)/(2 × 5)
⇒ Time = (60 × 18) = 1080 sec
⇒ Time = 1080 sec. = 1080/60 = 18 minutes
∴ The correct answer is 18 minutes.
A thief steals an item and escapes, running at a speed of 15 km/h. A policeman arrives at the spot of the crime after 4 minutes and immediately starts chasing the thief. 16 minutes after the policeman started to chase the thief; there is still a gap of 200 m between the two. At what distance from the spot of the crime will the policeman catch up the thief and what is the speed (in km/h) of the policeman?
Answer (Detailed Solution Below)
Thief Question 10 Detailed Solution
Download Solution PDFGiven:
Speed of thief = 15 km/hr
Formula used:
Distance = relative speed × time
Calculation:
Distance covered by thief in 20 minutes = 15 × (20/60) = 5 km
Since there is a gap of 200,m = 5 - 0.2 = 4.8 km.
Distance covered by a policeman in 16 minutes = 4.8 km
⇒ Speed of policeman × (16/60) = 4.8
⇒ Speed of policeman = (4.8 × 60)/16 = 18 km/hr
Now,
Distance = relative speed × time
⇒ 200 = (18 - 15) × (5/18) × time
⇒ Time = (200 × 18)/(3 × 5)
⇒ Time = 240 sec
Distance covered by thief = (15 × 240)/3600 = 1 km
Total distance covered by thief = 5 + 1 = 6 km
∴ The correct option is 2.
A thief is noticed by a policeman from a distance of 500 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 17 km/h and 20 km/h, respectively. What is the distance between them after 8 minutes?
Answer (Detailed Solution Below)
Thief Question 11 Detailed Solution
Download Solution PDFGiven:
Distance between policeman and thief in the starting = 500 m
Speed of policeman = 20 km/hr
Speed of thief = 17 km/hr
Concept: /Formula:
If the speed of a policeman and thief is x km/hr and y km/hr, then
Relative speed, if same directions = (x – y) km/hr
Distance between them after n hrs = (x – y) × n
1 km/hr = 5/18 m/sec
1 min = 60 sec
Calculation:
8 min = 8 × 60 = 480 seconds
Distance between policeman and thief in starting = 500 m
Relative speed of policeman and thief, if same directions = (20 – 17) = 3 × (5/18) = (5/6) m/sec
Distance covered in 480 seconds = (5/6) × 480 = 400 m
Distance between them after 480 seconds= 500 – 400 = 100 m
∴ Distance between them after 8 min is 100 m.
A thief steals an item and escapes, running at 20 km/h. A policeman arrives at the spot of the crime after 6 minutes and immediately starts chasing the thief. 24 minutes after the policeman started to chase the thief, there is still a gap of 400 m between the two. At what distance from the spot of crime would the policeman catch up with the thief, and what is the speed at which the policeman ran?
Answer (Detailed Solution Below)
Thief Question 12 Detailed Solution
Download Solution PDFGiven:
Speed of thief = 20 km/h
Policeman delay = 6 minutes
Time after which the gap is 400 m = 24 minutes
Gap = 400 m
Formula Used:
Distance = Speed × Time
km/h to m/min = multiply with 1000/60
Calculation:
Distance covered by thief in 6 min = 20 × 1000/60 × 6 min = 2000 m
Total time thief has been running when the gap is 400 m
⇒ 6 + 24 = 30 min
Distance covered by thief in 30 min = 20 × 1000/60 × 30 min = 10000 m
Distance covered by a policeman in 24 minutes
⇒ 10000 m - 400 m = 9600 m
Speed of policeman = 9600 m / 24 min = 400 m/min
Speed of policeman in km/h = 400 m/min × 60 min/1000 = 24 km/h
Relative speed = 400 m/min - (20 × 1000/60) m/min
⇒ 400 - 1000/3 = 200/3 m/min
Time to close 400 m gap = 400 / (200/3) = 6 min
Total distance from the spot of crime when the policeman catches the thief
⇒ Distance = (1000/3) × (30 + 6) = 12000 m = 12 km
∴ Running at a speed of 24 km/h, the policeman will catch the thief at a distance of 12 km from the spot of the crime.
A policeman follows a thief, who is 1250 m ahead of him. The policeman and the thief run at the speed of 10 km/h and 8 km/h, respectively. The distance (in km) run by the thief before he is nabbed by the policeman is:
Answer (Detailed Solution Below)
Thief Question 13 Detailed Solution
Download Solution PDFGiven:
Distance between policeman and thief in the starting = 1250 m
Speed of policeman = 10 km/hr
Speed of thief = 8 km/hr
Concept: /Formula:
If the speed of a policeman and thief is x km/hr and y km/hr, then
Relative speed, if same directions = (x – y) km/hr
Distance between them after n hrs = (x – y) × n
1 km/hr = 5/18 m/sec
1 min = 60 sec
Calculation:
Distance between policeman and thief in starting = 1250 m
Relative speed of policeman and thief, if same directions = (10 – 8) = 2 × (5/18) = (5/9) m/sec
Time is taken by a policeman to cover the gap = 1250/(5/9)
= 2250 sec
The distance (in km) run by the thief before he is nabbed by the policeman = 8 × 2250/3600
= 5 km
The distance (in km) run by the thief before he is nabbed by the policeman is 5 km.
A thief is spotted by a policeman from a distance of 400 m. When the policeman starts chasing, the thief also starts running. If the speed of the thief is 32 km/h and that of the policeman is 40 km/h, then how far would the thief have run before he is overtaken?
Answer (Detailed Solution Below)
Thief Question 14 Detailed Solution
Download Solution PDFGiven:
Distance between policeman and thief = 400 m
Speed of policeman = 40 km/h
Speed of thief = 32 km/h
Formula used:
Distance = relative speed × time
Calculation:
Distance = relative speed × time
⇒ 400 = (40 - 32) × (5/18) × time
⇒ 400 = 8 × (5/18) × time
⇒ Time = (400 × 18)/40 = 180 sec
Distance travelled by thief = 32 × (5/18) × 180
⇒ 32 × 5 × 10 = 1600 m
∴ The correct answer is 1600 m.
A policeman chases a thief. The speeds of the policeman and the thief are 8 km/h and 6 km/h, respectively. If the policeman started 10 minutes late, at what distance he will catch the thief?
Answer (Detailed Solution Below)
Thief Question 15 Detailed Solution
Download Solution PDFGiven:
Speed of thief = 6 km/h
Speed of policeman = 8 km/h
Formula Used:
Speed = Distance/Time
Concept Used:
If two objects are moving in the same direction with speeds S 1 and S 2 ,
Their relative speed is S 1 – S 2
Calculation:
Only the thief runs for 10 minutes.
Speed of thief in m/s = 6 km/h × 5/18 = 5/3 m/s
Time Taken in sec = 10 × 60 sec = 600 sec
Distance covered by the thief = Speed × Time
⇒ 5/3 m/s × 600 sec = 1000 m
Relative speed = 8 – 6 = 2 km/h
⇒ 2 × 5/18 m/s
⇒ 5/9 m/s
Time to catch the thief = Time required to cover 1000
⇒ 1000/5 × 9 s
⇒ 200 × 9 s
⇒ 1800 s = 30 min
Distance covered by the policeman in 30 min = 8 × 1/2
= 4 km.
∴ The policeman will catch the thief in 4 km.