Three or More Percentage MCQ Quiz - Objective Question with Answer for Three or More Percentage - Download Free PDF

Given:

Initial value of building (P_building) = ₹31,25,000

Depreciation rate of building (r_building) = 4%

Time (t_building) = 3 years

Initial value of land (P_land) = ₹32,00,000

Appreciation rate of land (r_land) = 5%

Time (t_land) = 3 years

Formula used:

For depreciation: A = P × (1 - r/100)^t

For appreciation: A = P × (1 + r/100)^t

Calculations:

For building value after 3 years (x):

A_building = P_building × (1 - r_building/100)^t_building

⇒ A_building = 31,25,000 × (1 - 4/100)³

⇒ A_building = 31,25,000 × (0.96)³

⇒ A_building = ₹27,64,800

For land value after 3 years (y):

A_land = P_land × (1 + r_land/100)^t_land

⇒ A_land = 32,00,000 × (1 + 5/100)³

⇒ A_land = 32,00,000 × (1.05)³

⇒ A_land = ₹37,04,400

Difference (y - x):

y - x = A_land - A_building

⇒ y - x = 37,04,400 - 27,64,800 = ₹9,39,600

∴ The correct answer is option (2).

Given:

Initial investment = ₹2,00,000

First day increase = 18%

Second day decrease = 15%

Third day decrease = 3%

Formula Used:

New Value = Initial Value × (1 + Percentage Change/100)

Net Percentage Change = [(Final Value - Initial Value) / Initial Value] × 100

Calculation:

Value after the first day:

⇒ ₹2,00,000 × (1 + 18/100)

⇒ ₹2,00,000 × 1.18

⇒ ₹2,36,000

Value after the second day:

⇒ ₹2,36,000 × (1 - 15/100)

⇒ ₹2,36,000 × 0.85

⇒ ₹2,00,600

Value after the third day:

⇒ ₹2,00,600 × (1 - 3/100)

⇒ ₹2,00,600 × 0.97

⇒ ₹1,94,582

Net Percentage Change:

⇒ [(₹1,94,582 - ₹2,00,000) / ₹2,00,000] × 100

⇒ [-₹5,418 / ₹2,00,000] × 100

⇒ -2.709%

Rounded to one decimal place:

⇒ -2.7%

The net percentage decrease in the value of the investor's shares is 2.7%.

Given:

A number is increased by 12%, then by 23%, and then decreased by 34%.

Formula Used:

For successive percentage changes:

Final Value = Initial Value × (1 + Percentage Change/100)ⁿ

Calculation:

Let the initial number be 100 (for simplicity).

After a 12% increase:

New Value = 100 × (1 + 12/100)

⇒ New Value = 100 × 1.12

⇒ New Value = 112

After a 23% increase:

New Value = 112 × (1 + 23/100)

⇒ New Value = 112 × 1.23

⇒ New Value = 137.76

After a 34% decrease:

New Value = 137.76 × (1 - 34/100)

⇒ New Value = 137.76 × 0.66

⇒ New Value = 90.9216

Net change in value = Final Value - Initial Value

Net change in value = 90.9216 - 100

Net change in value = -9.0784

Net percentage change = (Net change in value / Initial Value) × 100

Net percentage change = (-9.0784 / 100) × 100

Net percentage change = -9.0784%

The net decrease percent in the original number is appro×imately 9%.

Given:

The number first increased by 22%.

then same increased by 18%. 

The number, so obtained, is now decreased by 30% 

Calculation:

Let the number be 100x 

The number first increased by 22%.

⇒ \(100x \times \dfrac{122}{100} \) = 122x 

Now the same increased by 18%.

⇒ \(122x \times \dfrac{118}{100} \) = 143.96x 

Now decreased by 30%.

⇒ \(143.96x \times \dfrac{70}{100} \) = 100.77x

Net increase or decrease percent in the original number.

Given:

Initial value of building (P_building) = ₹31,25,000

Depreciation rate of building (r_building) = 4%

Time (t_building) = 3 years

Initial value of land (P_land) = ₹32,00,000

Appreciation rate of land (r_land) = 5%

Time (t_land) = 3 years

Formula used:

For depreciation: A = P × (1 - r/100)^t

For appreciation: A = P × (1 + r/100)^t

Calculations:

For building value after 3 years (x):

A_building = P_building × (1 - r_building/100)^t_building

⇒ A_building = 31,25,000 × (1 - 4/100)³

⇒ A_building = 31,25,000 × (0.96)³

⇒ A_building = ₹27,64,800

For land value after 3 years (y):

A_land = P_land × (1 + r_land/100)^t_land

⇒ A_land = 32,00,000 × (1 + 5/100)³

⇒ A_land = 32,00,000 × (1.05)³

⇒ A_land = ₹37,04,400

Difference (y - x):

y - x = A_land - A_building

⇒ y - x = 37,04,400 - 27,64,800 = ₹9,39,600

∴ The correct answer is option (2).

Given:

A number is increased by 12%, then by 23%, and then decreased by 34%.

Formula Used:

For successive percentage changes:

Final Value = Initial Value × (1 + Percentage Change/100)ⁿ

Calculation:

Let the initial number be 100 (for simplicity).

After a 12% increase:

New Value = 100 × (1 + 12/100)

⇒ New Value = 100 × 1.12

⇒ New Value = 112

After a 23% increase:

New Value = 112 × (1 + 23/100)

⇒ New Value = 112 × 1.23

⇒ New Value = 137.76

After a 34% decrease:

New Value = 137.76 × (1 - 34/100)

⇒ New Value = 137.76 × 0.66

⇒ New Value = 90.9216

Net change in value = Final Value - Initial Value

Net change in value = 90.9216 - 100

Net change in value = -9.0784

Net percentage change = (Net change in value / Initial Value) × 100

Net percentage change = (-9.0784 / 100) × 100

Net percentage change = -9.0784%

The net decrease percent in the original number is appro×imately 9%.

Given:

Initial investment = ₹2,00,000

First day increase = 18%

Second day decrease = 15%

Third day decrease = 3%

Formula Used:

New Value = Initial Value × (1 + Percentage Change/100)

Net Percentage Change = [(Final Value - Initial Value) / Initial Value] × 100

Calculation:

Value after the first day:

⇒ ₹2,00,000 × (1 + 18/100)

⇒ ₹2,00,000 × 1.18

⇒ ₹2,36,000

Value after the second day:

⇒ ₹2,36,000 × (1 - 15/100)

⇒ ₹2,36,000 × 0.85

⇒ ₹2,00,600

Value after the third day:

⇒ ₹2,00,600 × (1 - 3/100)

⇒ ₹2,00,600 × 0.97

⇒ ₹1,94,582

Net Percentage Change:

⇒ [(₹1,94,582 - ₹2,00,000) / ₹2,00,000] × 100

⇒ [-₹5,418 / ₹2,00,000] × 100

⇒ -2.709%

Rounded to one decimal place:

⇒ -2.7%

The net percentage decrease in the value of the investor's shares is 2.7%.

Given:

Initial value of building (P_building) = ₹31,25,000

Depreciation rate of building (r_building) = 4%

Time (t_building) = 3 years

Initial value of land (P_land) = ₹32,00,000

Appreciation rate of land (r_land) = 5%

Time (t_land) = 3 years

Formula used:

For depreciation: A = P × (1 - r/100)^t

For appreciation: A = P × (1 + r/100)^t

Calculations:

For building value after 3 years (x):

A_building = P_building × (1 - r_building/100)^t_building

⇒ A_building = 31,25,000 × (1 - 4/100)³

⇒ A_building = 31,25,000 × (0.96)³

⇒ A_building = ₹27,64,800

For land value after 3 years (y):

A_land = P_land × (1 + r_land/100)^t_land

⇒ A_land = 32,00,000 × (1 + 5/100)³

⇒ A_land = 32,00,000 × (1.05)³

⇒ A_land = ₹37,04,400

Difference (y - x):

y - x = A_land - A_building

⇒ y - x = 37,04,400 - 27,64,800 = ₹9,39,600

∴ The correct answer is option (2).

Given:

The number first increased by 22%.

then same increased by 18%. 

The number, so obtained, is now decreased by 30% 

Calculation:

Let the number be 100x 

The number first increased by 22%.

⇒ \(100x \times \dfrac{122}{100} \) = 122x 

Now the same increased by 18%.

⇒ \(122x \times \dfrac{118}{100} \) = 143.96x 

Now decreased by 30%.

⇒ \(143.96x \times \dfrac{70}{100} \) = 100.77x

Net increase or decrease percent in the original number.