A circular coil of radius 4m with the speed 35m/s is moving in a magnetic field perpendicular to it. If induced emf is of 60 V, then the value of magnetic field applied is 

  1. 0.0068 Wb/m2
  2. 0.068 Wb/m2
  3. 6.8 Wb/m2
  4. 68 Wb/m2

Answer (Detailed Solution Below)

Option 2 : 0.068 Wb/m2

Detailed Solution

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CONCEPT:

  • Motional emf: The emf induced due to motion relative to a magnetic field is called the motional emf. 

  • Consider a straight conductor PQ moving perpendicular to a uniform magnetic field B.
    • Assume the motion of the rod to be uniform with a constant velocity of (v m/s).
    • The rectangle PQRS forms a closed circuit enclosing a changing area due to the motion of the rod PQ.
  • The magnetic flux ϕ enclosed by the loop PQRS can be given as:

⇒ ϕ = B × area = B × (l.x)

  • Since the conductor is moving, there is a change in the rate of area moving. This causes a rate of change of flux which induces an emf.
  • This induced emf is given by:

Where   is the speed of the conductor PQ​

CALCULATION:

Given, length of the wire (l) = 2πr = 2π × 4 = 8π, magnetic field (B) = 4.5 Wb/m2, Induced emf (ε) = 60 V and velocity (v) =35 m/s

  • The emf induced in the coil can be calculated as

⇒ ε = Blv

The above equation can be written for magnetic field (B) as

  1. Hence option 2) is correct.

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