A hard disk has a rotational speed 6000 rpm. Its average latency time is

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NIMCET 2016 Official Paper

Answer 1

6000 rpm ≡ 6000 rotations per minute

6000 rotations → 1 minute

6000 rotations → 60 seconds

1 rotation → \({\rm{\;}}\frac{{60}}{{6000}}\; =10^{-2} s \)

Average latency time = ½ rotation

Average latency time = \(\frac{10^{-2}}{2} = \frac{10 \times 10^{-3}}{2} = 5 \times 10^{-3} s\)