Question
Download Solution PDFA uniform rod of cross-sectional area A and length L is subjected to an axial pull P. What is the change in length of the rod? (Assume that Young's modulus of elasticity E remains the same throughout the length.)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
We can find the change in length or longitudinal elongation by the formula:
\(\Delta L=\frac{Pl}{AE}\)
for this, we required Young Modulus of Elasticity E.
To find a decrease in the diameter of the rod, we need to know the Poisson's ratio (μ) defined as:
\(μ=-\frac{Lateral\;or\;diametral\;strain\;(ϵ_D)}{Longitudinal\;strain\;(ϵ_L)}\)
∴ Lateral deformation (ϵD) = -μ × Longitudinal deformation (ϵL)
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