Consider F1 & F2 be two equal and opposite force applied at an angle of 180° to each other as shown below and R is its resultant force, then what will be the magnitude of the resultant force

F2 J.S 13.6.20 Pallavi D3

  1. R = √ 3 F1
  2. R = 2 F1
  3. R = 0
  4. R = √ 2 F1

Answer (Detailed Solution Below)

Option 3 : R = 0
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Detailed Solution

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CONCEPT:

  • Law of Parallelogram of forces: This law is used to determine the resultant of two coplanar forces acting at a point.
    • It states that “If two forces acting at a point are represented in magnitude and direction by two adjacent sides of a parallelogram, then their resultant is represented in magnitude and direction by the diagonal of the parallelogram which passes through that common point.”

RRB JE ME 60 14Q EMech1 HIndi Diag(Madhu) 4

  • Let two forces F1 and F2, acting at the point O be represented, in magnitude and direction, by the directed line OA and OB inclined at an angle θ with each other.

Then if the parallelogram OACB be completed, the resultant force R will be represented by the diagonal OC.

\(R = \sqrt {F_1^2 + F_2^2 + 2{F_1}{F_2}cos\theta } \)

EXPLANATION:

Given that if two force F1 & F2 are equal and opposite to each then

F1 = F2

Angle between F1 & F2, θ = 180°

Thus, by applying the law of Parallelogram of forces we can conclude that:

\(R = \sqrt {F_1^2 + F_2^2 + 2{F_1}{F_2}cos180^\circ } \)

\(\therefore R = \sqrt {2F_1^2 + 2F_1^2 \times \left( { - 1} \right)}\)      ...(∵ cos 180° = -1)

\(\therefore R = \sqrt {2F_1^2 - 2F_1^2}\)

⇒ R = 0 N.

So option 3 is correct.

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