Find the solution set of m in the given consistent system of equations.

mx - 2y = 3
x + 2 my = m

Question

Question

Answer 1

Case 1: D ≠ 0

\(\left| {\begin{array}{*{20}{c}} m&{ - 2}\\ 1&{2m} \end{array}} \right|\) ≠ 0

2m² + 2 ≠ 0

m² + 1 ≠ 0

m²≠ -1

This is true for all values of m.

Case 2: D = 0

\(\left| {\begin{array}{*{20}{c}} m&{ - 2}\\ 1&{2m} \end{array}} \right| = 0\)

2m² + 2 = 0

m² + 1 = 0

m² = -1

This is never true.

∪ of both the cases is: m ϵ R