For no reflection condition, a vertically polarized wave should be incident at the interface between two dielectrics having ϵ1 = 4 and ϵ2 = 9, with an incident angle of 

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ESE Electronics 2011 Paper 1: Official Paper
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  1. \(tan^{-1}(\frac{9}{4})\)
  2. \(tan^{-1}(\frac{3}{2})\)
  3. \(tan^{-1}(\frac{2}{3})\)
  4. \(tan^{-1}(\frac{4}{9})\)

Answer (Detailed Solution Below)

Option 2 : \(tan^{-1}(\frac{3}{2})\)
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Detailed Solution

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Concept:

Brewster’s Angle:  Brewster's angle is an angle of incidence at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface, with no reflection.

\(tan{\theta _i} = \sqrt {\frac{{{\epsilon_2}}}{{{\epsilon_1}}}} \)----(1)

Calculation:

For no reflection incident wave should be completely transmitted to another medium at Brewster angle.

Given:

ϵ2 = 9, ϵ1 = 4

From equation (1) we get,

\(tan{\theta _i} = \sqrt {\frac{9}{4}} \)

\({\theta _i} = {\tan ^{ - 1}}\frac{3}{2}\)

Note: Brewster angle does not affect S polarized waves.

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