Question
Download Solution PDFFor parallel polarisation, for lossless dielectrics, the expression for Brewster angle for a wave traveling from medium 1 to the medium of refractive indices η1, and η2 respectively is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The Brewster law states the relationship between light waves and polarized light. The polarized light vanishes at this maximum angle.
Brewster angle is the angle when a wave is an incident on the surface of a perfect dielectric at which there is no reflected wave and the incident wave is parallelly polarised.
For an elliptically polarized wave incident on the interface of a dielectric, the reflected wave will be elliptically polarized
Brewster angle is given by:
\(\theta = {\tan ^{ - 1}}\sqrt {\frac{{{\epsilon_2}}}{{{\epsilon_1}}}}\)
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