Question
Download Solution PDF(2, - 3) पर केंद्र और त्रिज्या 5 इकाई वाले एक वृत्त का समीकरण ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
(h, k) पर केंद्र और त्रिज्या 'r' वाले वृत्त का समीकरण निम्न है
(x - h)2 + (y - k)2 = r2
गणना:
हम जानते हैं कि (h, k) पर केंद्र और त्रिज्या 'r' वाले वृत्त का समीकरण निम्न है
(x - h)2 + (y - k)2 = r2
यहाँ, केंद्र (h, k) = (2, - 3) और त्रिज्या r = 5 इकाई।
इसलिए, (2, - 3) पर केंद्र और त्रिज्या 5 इकाई वाले एक वृत्त का समीकरण निम्न है
(x - 2)2 + (y + 3)2 = 52
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अतः (2, - 3) पर केंद्र और त्रिज्या 5 इकाई वाले एक वृत्त का समीकरण
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