Question
Download Solution PDFफ्रेऑन - 12 का रासायनिक सूत्र क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
प्रशीतक का सामान्य रासायनिक सूत्र CmHnFpClq. है
और प्रशीतक का प्रतिनिधित्व करने के लिए संकेत
R - (m - 1)(n + 1)p
और n + p + q = 2 m + 2
गणना:
दिया गया:
प्रशीतक फ्रीन -12 = R - 012
जैसा कि हम जानते हैं, R - (m - 1)(n + 1)p
m - 1 = 0 ⇒ m = 1
n + 1 = 1 ⇒ n = 0
p = 2
अब, n + p + q = 2m + 2
0 + 2 + q = 2 × 1 + 2
∴ q = 2
∴ CmHnFpClq = CCl2F2
Last updated on Mar 26, 2025
-> UKPSC JE Notification for 2025 will be out soon!
-> The total number of vacancies along with application dates will be mentioned in the notification.
-> The exam will be conducted to recruit Junior Engineers through Uttarakhand Public Service Commission.
-> Candidates with an engineering diploma in the concerned field are eligible.
-> The selection process includes a written exam and document verification. Prepare for the exam with UKPSC JE Previous Year Papers.