Question
Download Solution PDFरेखा ST का चुंबकीय अक्षांश 122°40' है और उस स्थान पर चुंबकीय दिक्पात 20°20' पश्चिम है। रेखा का वास्तविक अक्षांश कितना होगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंप्रत्यय:
वास्तविक अक्षांश (TB) = चुंबकीय अक्षांश (MB) ± दिक्पात
(पूर्वी दिक्पात के लिए +ve और पश्चिमी दिक्पात के लिए -ve का प्रयोग करें)
परिकलन:
वास्तविक अक्षांश (TB) = चुंबकीय अक्षांश (MB) - दिक्पात
इसलिए TB = 122° 40' - 20° 20' = 102°20'
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