दिए गए समीकरण को सही करने के लिए कौन-सी दो संख्याओं को आपस में बदलना होगा?

55 + 32 - 4 × (1 × 12) + (16 ÷ 4) = 31 

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  1. 16 और 32
  2. 55 और 32
  3. 12 और 32
  4. 12 और 16

Answer (Detailed Solution Below)

Option 1 : 16 और 32
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Detailed Solution

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1) 16 और 32

दिया गया समीकरण: 55 + 32 – 4 × (1 × 12) + (16 ÷ 4) = 31

 ‘16 और 32’ को परस्पर बदलने के बादहमें मिलता है:

बायां पक्ष = 55 + 16 – 4 × (1 × 12) + (32 ÷ 4)

= 55 + 16 – 4 × 12 + 8

= 55 + 16 – 48 + 8

= 79 – 48

= 31 = दायां पक्ष

2) 55 और 32

दिया गया समीकरण: 55 + 32 – 4 × (1 × 12) + (16 ÷ 4) = 31

 ‘55 और 32’ को परस्पर बदलने के बाद, हमें मिलता है:

बायां पक्ष, = 32 + 55 – 4 × (1 × 12) + (16 ÷ 4)

= 32 + 55 – 4 × 12 + 4

= 32 + 55 – 48 + 4

= 32 + 23 + 3

= 58 ≠ दायां पक्ष

3) 12 और 32

दिया गया समीकरण: 55 + 32 – 4 × (1 × 12) + (16 ÷ 4) = 31

 ‘12 और 32’ को परस्पर बदलने के बाद, हमें मिलता है:

बायां पक्ष = 55 + 12 – 4 × (1 × 32) + (16 ÷ 4)

= 55 + 12 – 4 × 32 + 4

= 55 + 12 – 128 + 4

= 71 – 128

= - 57 ≠ दायां पक्ष

4) 12 और 16

दिया गया समीकरण: 55 + 32 – 4 × (1 × 12) + (16 ÷ 4) = 31

 ‘12 और 16’ को परस्पर बदलने के बाद, हमें मिलता है:

बायां पक्ष = 55 + 32 – 4 × (1 × 16) + (12 ÷ 4)

= 55 + 32 – 4 × 16 + 3

= 55 + 32 – 64 + 3

= 90 – 64

= 26 ≠ दायां पक्ष

अतः, सही उत्तर ‘16 और 32’ है।

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-> Bihar Police Exam Date 2025 for Written Examination will be conducted on 16th, 20th, 23rd, 27th, 30th July and 3rd August 2025.

-> The Bihar Police City Intimation Slip for the Written Examination will be out from 20th June 2025 at csbc.bihar.gov.in.

-> A total of 17 lakhs of applications are submitted for the Constable position.

-> The application process was open till 18th March 2025.

-> The selection process includes a Written examination and PET/ PST. 

-> Candidates must refer to the Bihar Police Constable Previous Year Papers and Bihar Police Constable Test Series to boost their preparation for the exam.

-> Assam Police Constable Admit Card 2025 has been released.

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