Question
Download Solution PDFदिलेले समीकरण दुरुस्त करण्यासाठी कोणत्या दोन संख्यांची अदलाबदल करावी लागेल?
55 + 32 - 4 × (1 × 12) + (16 ÷ 4) = 31
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF1) 16 आणि 32
दिलेले समीकरण: 55 + 32 - 4 x (1 x 12) + (16 ÷ 4) = 31
'16 आणि 32' यांची अदलाबदल केल्यानंतर, आपल्याला मिळते:
LHS = 55 + 16 - 4 x (1 x 12) + (32 ÷ 4)
= 55 + 16 - 4 x 12 + 8
= 55 + 16 - 48 + 8
= 79 - 48
= 31 = उजव्या हाताची बाजू
2) 55 आणि 32
दिलेले समीकरण: 55 + 32 - 4 x (1 x 12) + (16 ÷ 4) = 31
'55 आणि 32' यांची अदलाबदल केल्यानंतर, आपल्याला मिळते:
LHS = 32 + 55 - 4 x (1 x 12) + (16 ÷ 4)
= 32 + 55 - 4 x 12 + 4
= 32 + 55 – 48 + 4
= 32 + 23 + 3
= 58 ≠ उजव्या हाताची बाजू
3) 12 आणि 32
दिलेले समीकरण: 55 + 32 - 4 x (1 x 12) + (16 ÷ 4) = 31
'12 आणि 32' यांची अदलाबदल केल्यानंतर,आपल्याला मिळते:
LHS = 55 + 12 - 4 x (1 x 32) + (16 ÷ 4)
= 55 + 12 - 4 x 32 + 4
= 55 + 12 - 128 + 4
= 71 - 128
= - 57 ≠ उजव्या हाताची बाजू
4) 12 आणि 16
दिलेले समीकरण: 55 + 32 - 4 x (1 x 12) + (16 ÷ 4) = 31
'12 आणि 16' यांची अदलाबदल केल्यानंतर, आपल्याला मिळते:
LHS = 55 + 32 - 4 x (1 x 16) + (12 ÷ 4)
= 55 + 32 - 4 x 16 + 3
= 55 + 32 – 64 + 3
= 90 - 64
= 26 ≠ उजव्या हाताची बाजू
म्हणून, '16 आणि 32' हे योग्य उत्तर आहेLast updated on Jun 30, 2025
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