Question
Download Solution PDFIn the given figure, ∠BOQ = 60° and AB is diameter of the circle. Find ∠ABO.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFUsing the theorem, angle in the semi-circle is a right angle,
⇒ ∠BOA = 90°
Theorem: The alternate segment theorem states that an angle between a tangent and a chord through the point of contact is equal to the angle in the alternate segment.
⇒ ∠BOQ = ∠BAO = 60°
In ΔABO,
Sum of the angles of the triangle is 180°
⇒ ∠ABO = 180° – ∠BOA – ∠BAO = 180° – 90° – 60° = 30°
Last updated on Jul 12, 2025
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