Question
Download Solution PDFKamal travels from City A to City B. If Kamal drives his car at 3/4 of his normal speed, then he reaches City B 45 minutes late.
Find the time (in minutes) that Kamal would have taken to travel from City A to City B if he drove at his normal speed.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Speed = (3/4) of normal speed
Delay = 45 minutes
Formula used:
Time = Distance / Speed
If time at normal speed = x minutes, then
Distance = Speed × Time = s × x
Calculation:
At reduced speed (3/4)s, time = x + 45
⇒ s × x = (3/4)s × (x + 45)
⇒ x = (3/4)(x + 45)
⇒ 4x = 3x + 135
⇒ x = 135
∴ Time at normal speed = 135 minutes
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