Question
Download Solution PDFसरासरी 45 किमी/तास वेगाने एक ट्रेन वेळेवर आपल्या गंतव्यस्थानी पोहोचते. जर ट्रेन सरासरी 30 किमी/तास वेगाने धावली, तर ट्रेनला 15 मिनिटे उशीर हाेताे. एकूण प्रवास किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
वास्तविक वेग = 45 किमी/तास
कमी झालेला वेग = 30 किमी/तास
वापरलेले सूत्र:
एकूण अंतर =
येथे,
S1 = वास्तविक वेग
S2 = कमी झालेला वेग
T1 = वेळ1
T2 = वेळ2
गणना:
संकल्पनेनुसार,
एकूण अंतर =
⇒
⇒ 22.5 किमी
∴ A आणि B मधील अंतर 22.5 किमी आहे.
Last updated on Jul 15, 2025
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