ఒకవేళ a + b + c = 0 మరియు ab + bc + ca = -11 అయితే, a2 + b2 + cవిలువ ఎంత?

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SSC CHSL Tier-I Exam 2022 Official Paper (Held On: 17 March, 2023 Shift 1)
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  1. -11
  2. 22
  3. 0
  4. 11

Answer (Detailed Solution Below)

Option 2 : 22
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SSC CHSL General Intelligence Sectional Test 1
25 Qs. 50 Marks 18 Mins

Detailed Solution

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ఇచ్చినది:

a + b + c = 0 మరియు ab + bc + ca = -11

ఉపయోగించిన సూత్రం:

(a + b + c)2 = a2 + b2 + c2 + 2 (ab + bc + ca)

గణన:

ఉపయోగించిన సూత్రం ప్రకారం

⇒ (0)2 = a2 + b2 + c2 + 2 × (-11)

⇒ 0 = a2 + b2 + c2 - 22

⇒ a2 + b2 + c2 = 22

ఎంపిక 2 సరైన సమాధానం.

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