The quantity of charge required to obtain one mole of f aluminium  from Al₂O₃ is ___________. 

CONCEPT:

Faraday's Laws of Electrolysis

• Faraday's first law states that the amount of substance deposited or liberated at an electrode during electrolysis is directly proportional to the quantity of electricity that passes through the electrolyte.
• Faraday's second law states that the quantities of different substances liberated or deposited by the same quantity of electricity passing through the electrolyte are directly proportional to their chemical equivalent weights.

EXPLANATION:

• To obtain one mole of aluminum (Al) from aluminum oxide (Al₂O₃), we need to consider the balanced half-reaction:

  Al₂O₃ + 6e^- → 2Al

• From the half-reaction, 6 moles of electrons (6F, where F is Faraday's constant) are required to produce 2 moles of Al.
• Therefore, to obtain 1 mole of Al, we need half the number of electrons:
  • 6F / 2 = 3F

Therefore, the quantity of charge required to obtain one mole of aluminum from Al₂O₃ is 3F.