Question
Download Solution PDFWhat is the value of normal stress in an oblique plane, when θ = 90°? (Here, θ is the angle of the cutting plane forms with the normal plane.)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Member subjected to direct stress in one plane:
When a member is subjected to direct stress (σ) in one plane, the normal and shear stress on an oblique plane at an angle ϕ to the direction perpendicular of the direction of force is:
Normal stress, σθ = σx cos2 θ
Tangential or shear stress, τ = \(\frac{σ_x}{2}\sin{2 θ}\)
Where, σ = \(\frac{P}{A}\)
P is the normal force due to stress and A is the area of cross-section of the member.
Explanation:
Given:
θ = 90°
Normal stress,
σθ = σx cos290°
⇒ σθ = 0
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