When a body of mass 'm' attains a velocity 'v' from rest in time 't', then kinetic energy of translation is:

Question

Question

This question was previously asked in

JKSSB JE ME 2015 Official Paper

Answer 1

Explanation:

Kinetic energy (K.E):

The energy possessed by a body by the virtue of its motion is called kinetic energy.

The expression for kinetic energy is given by:

\(KE = \frac{1}{2}m{v^2}\) = 0.5 mv²

Where m = mass of the body and v = velocity of the body

Additional Information

Momentum (p): The product of mass and velocity is called momentum.

Momentum (p) = mass (m) × velocity (v)

The relationship between the kinetic energy (KE or k) and Linear momentum is given by:

As we know,

\(KE = \frac{1}{2}m{v^2}\)

Divide numerator and denominator by m, we get

\(KE = \frac{1}{2}\frac{{{m^2}{v^2}}}{m} = \frac{1}{2}\frac{{\;{{\left( {mv} \right)}^2}}}{m} = \frac{1}{2}\frac{{{p^2}}}{m}\;\) [p = mv]

\(\therefore KE = \frac{1}{2}\frac{{{p^2}}}{m}\;\)

\(p = \sqrt {2mKE} \)