Question
Download Solution PDFA 3-phase, 1500 KVA, 6600 v, star-connected alternator has 9 slots per pole and 6 conductors per slot. The output of this alternator on a particular load is given by 1200 KW and total losses of the machine is equal to 55 kW. What is the value of percentage efficiency?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFRating of the alternator
An alternator is an electrical machine that converts mechanical input to electrical output.
The rating of an alternator always indicates the output electrical parameters.
The efficiency of the alternator is given by:
\(η = {Output \space power \over Output \space power\space + \space Losses}\)
Calculation
Given, Rating of the alternator: A 3-phase, 1500 KVA, 6600 V, 1200 KW
Pout = 1200 kW
Losses = 55 kW
\(η ={1200 \over 1200 + 55}\)
% η = 95.62
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