A body is subjected to a direct tensile stress (σ) in one plane. The shear stress is max at a section inclined at ____ to the normal of the section.

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ISRO VSSC Technical Assistant Mechanical 7 April 2012 Official Paper
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  1. 45° and 90°  
  2. 45° and 135°
  3. 60° and 150°
  4. 30° and 135°

Answer (Detailed Solution Below)

Option 2 : 45° and 135°
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Detailed Solution

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Concept:

Shear stress formula for complex loading is given by;

where σx = stress in x-direction, σy = stress in y-direction, τxy = shear stress in xy plane, τθ  = shear stress in a plane at angle θ 

Calculation:

Given:

σx = σ,  σy = 0, τxy = 0

Now the relation becomes 

Now the value of shear stress will be maximum for the maximum value of sin 2θ and for θ = 45° and θ = 135° value of sin 2θ will be maximum that is 1 hence shear stress will be maximum on these planes.

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