Question
Download Solution PDFA person starts from point X and moves 6 km towards the East. He turns left and moves 3 km, takes a left turn, and moves 5 km. He turns right and moves 2 km and then turns left and moves 1 km and reaches a point Y. How much and in which direction does he need to move now to reach point X?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFrom the given information:
Step 1: A person starts from point X and moves 6 km towards the East. He turns left and moves 3 km, takes a left turn, and moves 5 km.
Step 2: He turns right and moves 2 km and then turns left and moves 1 km and reaches point Y.
Distance from Y to X = 3 + 2 = 5 km
From the diagram, we can see that the distance from Point Y to Point X is 5 km toward the south.
Hence, the correct answer is option 1).
Last updated on Jul 1, 2025
-> SSC JE notification 2025 for Civil Engineering has been released on June 30.
-> Candidates can fill the SSC JE CE application from June 30 to July 21.
-> SSC JE Civil Engineering written exam (CBT-1) will be conducted on 21st to 31st October.
-> The selection process of the candidates for the SSC Junior Engineer post consists of Paper I, Paper II, Document Verification, and Medical Examination.
-> Candidates who will get selected will get a salary range between Rs. 35,400/- to Rs. 1,12,400/-.
-> Candidates must refer to the SSC JE Previous Year Papers and SSC JE Civil Mock Test, SSC JE Electrical Mock Test, and SSC JE Mechanical Mock Test to understand the type of questions coming in the examination.
-> The Staff Selection Commission conducts the SSC JE exam to recruit Junior Engineers in different disciplines under various departments of the Central Government.