Question
Download Solution PDFA simply supported RCC beam of effective length 5 m and section of size 200 mm × 300 mm is having flexural strength of 18 kN-m. Calculate the maximum external udl that can be applied to the beam before failure. Take self-weight as 1 kN/m.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Given:
Section of beam: 200 mm x 300 mm
Effective length: 5 m
Flexural strength: 18 kN-m
Self-weight: 1 kN/m
We know that the maximum bending moment for a uniformly distributed load on a simply supported beam is given by:
\(M_{\text{max}} = \frac{w_u \cdot L^2}{8} \)
Where:
\(w_u\)= Factored load (kN/m)
\(L\)= Effective length of the beam (m)
\(M_{(max)}\)= Maximum bending moment (kN-m)
\(\text{Factored load } (W_u) = w_{\text{applied}} + w_{\text{self}} = w + 1 \)
\(\therefore 18 = \frac{(w + 1) \times 5^2}{8} \)
\(W = 4.76 \, \text{kN/m} \)
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