Anil completed a certain journey by a car. If he covered 35% of the distance at 70 km/h. 40% of the distance at 80 km/h and the remaining distance at 50 km/h, his average speed (in km/h) for the entire journey is:

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SSC CHSL Exam 2023 Tier-I Official Paper (Held On: 09 Aug, 2023 Shift 1)
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  1. 66\(\frac{3}{3}\)km/h
  2. 66\(\frac{2}{3}\)km/h
  3. 66\(\frac{1}{3}\)km/h
  4. 66\(\frac{4}{3}\)km/h

Answer (Detailed Solution Below)

Option 2 : 66\(\frac{2}{3}\)km/h
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Detailed Solution

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Given:

Anil covers his 35% of journey with speed = 70 km/h

Covers 40% of the journey with speed = 80 km/h

Remaining distance at speed = 50 km/h

Formula used:

Average speed = total distance/total time taken

Calculation:

Let Anil covers total distance = 100 km

Time taken by Anil to cover 35 km = 35/70 = 1/2 h

Time taken by Anil to cover the next 40 km = 40/80 = 1/2 h

Time taken by Anil to cover the remaining 25 km = 25/50 = 1/2 h

Average speed = total distance/total time taken

⇒ 100/(0.5 + 0.5 + 0.5)

⇒ 1000/15

⇒ 200/3 = 66\(\frac{2}{3}\) km/h

∴ The correct answer is  66\(\frac{2}{3}\) km/h.

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