Find the HCF of (4315 − 1) and (425 − 1).

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SSC MTS Previous Year Paper (Held on: 26 July 2022 Shift 1)
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  1. 1
  2. (425 − 1)
  3. 1024
  4. 1023

Answer (Detailed Solution Below)

Option 4 : 1023
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Detailed Solution

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Given:

(4315 − 1) and (425 − 1)

Concept used:

HCF of (am − 1) and (an − 1) is (aHCF(m,n) − 1).

Calculations:

HCF(315, 25) = 5

According to the concept,

HCF {(4315 − 1), (425 − 1)} 

= (4HCF(315, 25) − 1)

= (45 − 1)

= 1024 − 1

= 1023

Hence, The Required value is 1023.

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