Question
Download Solution PDFवक्र x2y2 = a2(x2 + y2)के लिए, निर्देशांक अक्षों के समानांतर अनन्तस्पर्शी हैं
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसही उत्तर विकल्प 2 है।
दिया गया है: वक्र x2y2 = a2(x2 + y2),
गणना:
⇒ x2y2 = a2(x2 + y2),
⇒ x2 (y2 - a2) - (y2 a2) = 0
X की उच्चतम शक्ति x2 है
x2 का गुणांक y2 - a2 है
x-अक्ष के समानांतर अनन्तस्पर्शी इस प्रकार दिए गए हैं:
⇒ y2 - a2 = 0
⇒ y = ± a
y की उच्चतम शक्ति y2 है और इसका गुणांक x2 - a2 है
y-अक्ष के समानांतर अनन्तस्पर्शी इस प्रकार दिए गए हैं:
x2 - a2 = 0
x = ± a
Last updated on Jun 27, 2025
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