यदि Sin θ = \(\frac{4}{5}\) है, तो tan θ - Cot θ का मान ज्ञात कीजिए।

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SSC CGL 2023 Tier-I Official Paper (Held On: 17 Jul 2023 Shift 2)
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  1. \(\frac{5}{12}\)
  2. \(\frac{7}{9}\)
  3. \(\frac{7}{12}\)
  4. \(\frac{7}{8}\)

Answer (Detailed Solution Below)

Option 3 : \(\frac{7}{12}\)
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Detailed Solution

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दिया गया है:

Sin θ = 4/5

प्रयुक्त सूत्र:

tan θ = P/B ; cot θ = B/P

पाइथागोरस प्रमेय द्वारा:

⇒ H2 = P2 + B2 

जहाँ, P = लंब; B = आधार; H = कर्ण

गणना:

tan θ = P/B ; cot θ = B/P

पाइथागोरस प्रमेय द्वारा:

⇒ H2 = P2 + B2

⇒ 52 = 42 + B2

⇒ B2 = 52 - 42

⇒ B = √(25 - 16) = √9

⇒ B = 3

tan θ - Cot θ

⇒ (P/B) - (B/P) 

⇒ (4/3) - (3/4) = (16 - 9)/12

⇒ 7/12

∴ सही उत्तर 7/12 है।

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