Question
Download Solution PDFएक वृत्त की दो जीवाएँ \(\rm \overline{AB}\) और \(\rm \overline{CD}\) वृत्त के बाह्य बिंदु P पर मिलती हैं। यदि m(\(\rm \overline{AP}\)) = 200 मिमी, m(\(\rm \overline{AB}\)) = 120 और m(\(\rm \overline{CP}\)) = 160 मिमी है, तब \(\rm \overline{CD}\) की लंबाई कितनी है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है :
m(\(\rm \overline{AP}\)) = 200 मिमी, m(\(\rm \overline{AB}\)) = 120 मिमी और m(\(\rm \overline{CP}\)) = 160 मिमी
गणना :
माना, CD की लंबाई x है।
⇒ AP × BP = CP × DP
⇒ 200 × 80 = 160 × (160 -x)
⇒ 16000 = 160 × (160 -x)
⇒ 16000 = 25600 - 160x
⇒ x = 9600/160
⇒ x = 60 मिमी
∴ सही उत्तर 60 मिमी है।
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