Question
Download Solution PDFHow much energy is used by an 80% efficient, 2kW (input) motor running at a peak load for 5 hours?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Efficiency (η) = (Output power)/(Input power)
Energy = (Power) (Time)
Calculation:
Output power = (Input power) (Efficiency) = 2 x 0.8
Output power = 1.6 kW
Output energy = 1.6 x 5 = 8 kWhLast updated on Jun 11, 2025
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