If the inner radius of a hemispherical bowl is 5 cm and its thickness is 0.25 cm, then find the volume of the material required in making the bowl. (use π = \(\frac{22}{7}\)) (Rounded up to two places of decimals).

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SSC CGL 2023 Tier-I Official Paper (Held On: 21 Jul 2023 Shift 4)
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  1. 34 cm3
  2. 44 cm3
  3. 45.34 cm3
  4. 41.28 cm3

Answer (Detailed Solution Below)

Option 4 : 41.28 cm3
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Detailed Solution

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Given:

If the inner radius of a hemispherical bowl is 5 cm and its thickness is 0.25 cm, then find the volume of the material required in making the bowl.

Concept used:

Volume fo hemisphere = 2/3 π(R3 - r3)

Calculation:

The volume will be,

2/3 π(R3 - r3)

⇒ 2/3 × 22/7 (5.253 - 53)

⇒ 44/21 × (144.7 - 125)

⇒ 44/21 × 19.7

⇒ 866.8 / 21

⇒ 41.276 ≈ 41.28 cm3

∴ The correct option is 4

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