Question
Download Solution PDFIf the voltage across a 5μF capacitor is V(t) = 40 cos(6000t) volt, then the current through it is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option1):(-1.2 sin(6000t) amp)
Concept:
The current through the capacitor at the moment is equal to
i(t) = C \(dv\over dt\)
where
v(t) is the voltage
Calculation:
Given
C = 5 × 10-6 F
V(t) = 40 Cos(6000t)
i(t) = C \(dv\over dt\)
= 5 × 10-6 \(d\over dt\)(40 Cos(6000t) )
= - 5 × 10-6 × 6000 × 40 sin 6000t
= - 1.2 sin 6000t A
Last updated on Jun 16, 2025
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