In ΔABC, MN∥BC, the area of quadrilateral MBCN = 130 cm2. If AN : NC = 4 : 5, then the area of ΔMAN is:

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SSC CGL Previous Paper 65 (Held On: 3 March 2020 Shift 1)
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  1. 45 cm2
  2. 65 cm2
  3. 40 cm2
  4. 32 cm2

Answer (Detailed Solution Below)

Option 4 : 32 cm2
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F1 A.K 13.5.20 Pallavi D1

Given,

the area of quadrilateral MBCN = 130 cm2.

AN : NC = 4 : 5

Hence, AC = 4 + 5 = 9

In ΔABC, If MN∥BC, then

Area of ΔAMN/area of ΔABC = (AN/AC)2

Area of ΔAMN/area of ΔABC = (4/9)2 = 16/81

Area of ΔAMN = 16 unit and area of ΔABC = 81 unit

Now, Area of quadrilateral MBCN = area of ΔABC - area of ΔAMN

⇒ 81 - 16 unit = 130 cm2

⇒ 65 unit = 130 cm2

⇒ 1 unit = 130/65 = 2 cm2

∴ Area of ΔAMN = 16 × 2 = 32 cm2
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