Question
Download Solution PDFIn an irrigated field, the net irrigation requirement is 15 cm, the application efficiency is 80% and water conveyance efficiency is 60%. What is the gross irrigation requirement (in cm)?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Gross Irrigation Requirement, GIR = \(\frac{{Net\;Irrigation\;Requirement\left( {NIR} \right)}}{{{\eta _a} \times {\eta _c}\;}}\)
Where ηa and ηc are the application and conveyance efficiency respectively.
Calculation:
Given,
ηa = 80 %
ηc = 60 %
NIR = 15 cm
\({\rm{GIR}} = \frac{{15\;cm}}{{0.8 \times 0.6}} = 31.25\;cm\)
Last updated on May 28, 2025
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