Question
Download Solution PDFA आणि B मिळून 50 दिवसांत एक कार्य करू शकतात. जर A हा B पेक्षा 40% कमी कार्यक्षम असेल, तर एकटा A हा 60% कार्य किती दिवसात पूर्ण करू शकेल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
A आणि B मिळून 50 दिवसांत एक कार्य करू शकतात.
A हा B पेक्षा 40% कमी कार्यक्षम आहे
संकल्पना:
एकूण कार्य = कामगारांची कार्यक्षमता × त्यांना लागणारा वेळ
गणना:
B ची कार्यक्षमता 5a समजा
म्हणून, A ची कार्यक्षमता = 5a × 60%
⇒ 3a
म्हणून, त्यांची एकूण कार्यक्षमता = 8a
एकूण कार्य = 8a × 50
⇒ 400a
आता,
कार्याचे 60% = 400a × 60%
⇒ 240a
आता,
आवश्यक वेळ = 240a/3a
⇒ 80 दिवस
∴ एकटा A हा 60% कार्य 80 दिवसात पूर्ण करू शकेल.
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