Question
Download Solution PDF2 किलोग्रॅम वस्तुमानाची वस्तू 20 मी/से.च्या प्रारंभिक वेगाने वर फेकली जाते. 2 सेकंदांनंतर, तिची गतिज ऊर्जा किती असेल? (g = 10 मी/से2)
Answer (Detailed Solution Below)
Detailed Solution
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- गतिज उर्जेची व्याख्या m वस्तुमानाच्या वस्तूला एका बिंदूपासून दुसर्‍या बिंदूकडे निर्दिष्ट वेग v सह हलविण्यासाठी आवश्यक ऊर्जा म्हणून केली जाते.
- न्यूटनचे गतीचे पहिले समीकरण वापरून,
v = u + at
जिथे v = वस्तूचा अंतिम वेग
- u = वस्तूचा प्रारंभिक वेग
- a = वस्तूचे त्वरण
- t = वस्तूने घेतलेला वेळ
जशी, वस्तू वरच्या दिशेने जात आहे, a = -g, जिथे g = गुरुत्वीय त्वरण
म्हणून, v = u – gt
दिलेले आहे, u = 20 मी/से, t = 2 सेकंद आणि g = 10 मी/से2
वरील सूत्रात ठेवल्यावर, आपल्याला मिळेल,
v = 20 – 10 × 2 = 0
K.E. = ½ mv2 वापरून
जिथे, K.E. = वस्तूची गतिज ऊर्जा
- m = वस्तूचे वस्तुमान
- v = वस्तूचा अंतिम वेग
मूल्ये टाकल्यावर, K.E. = ½ × 2 × 0 = 0 J
म्हणून, 2 किलो वस्तुमानाच्या वस्तूची गतिज ऊर्जा शून्य आहे.Last updated on Jul 17, 2025
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